Ask question

Ask question

All categories

2 years ago

12

A packet of crisps weighs 32 grams to the nearest gram. A multipack contains 10 packets. Work out the least and greatest weight

of the multipack

1 answer:

bogdanovich [222]2 years ago

3 0

3 divided by 10 I’ve had that question before
Hope this helped if it’s wrong ummm sorry but I’m sure it’s not because I’ve had it before

You might be interested in

F(x, y) = x2 + y2 + 4x − 4y, x2 + y2 ≤ 81 find the extreme values of f on the region described by the inequality.

Whitepunk [10]

Take partial derivatives and set them equal to 0:

$\nabla F(x,y)=\langle2x+4,2y-4\rangle=\mathbf 0$

We find one critical point within the boundary of the disk at $(x,y)=(-2,2)$ . The Hessian matrix for this function is

$\mathbf H(x,y)=\begin{bmatrix}f_{xx}&f_{xy}\\f_{yx}&f_{yy}\end{bmatrix}=\begin{bmatrix}2&0\\0&2\end{bmatrix}$

which is positive definite, and incidentally independent of $x$ and $y$ , so $F(x,y)$ attains a minimum $F(-2,2)=-8$ .

Meanwhile, we can parameterize the boundary by $\mathbf r(t)=\langle9\cos t,9\sin t\rangle$ with $0\le t\le2\pi$ , which gives

$F(x,y)=F(x(t),y(t))=f(t)=81\cos^2t+81\sin^2t+36\cos t-36\sin t=81+36(\cos t-\sin t)$

with critical points at

$f'(t)=0\implies 36(-\sin t-\cos t)=0\implies\sin t+\cos t=0\implies t=\dfrac{3\pi}4,\dfrac{7\pi}4$

At these points, we get

$f\left(\dfrac{3\pi}4\right)=81-36\sqrt2\approx30.0883$
$f\left(\dfrac{7\pi}4\right)=81+36\sqrt2\approx131.9117$

so we attain a maximum only when $t=\dfrac{7\pi}4$ , which translates to $(x,y)=\left(\dfrac9{\sqrt2},-\dfrac9{\sqrt2}\right)$ .

3 0

2 years ago

An animal park has lions, tigers and zebras. 17% of the animals are zebras. What percentage are tigers? Show me your work!

antoniya [11.8K]

Answer:

53% are tigers

Step-by-step explanation:

If you were referring to the question:

<u><em>An animal park has lions, tigers and zebras. 17% of the animals are lions and 3/10 of the animals are zebras. What percentage are tigers? Show me your work! </em></u>

We can then solve it by considering what is 3/10 in percent form.

When you think of percent, just remember that it is a portion for every 100. So think of a fraction that is proportional to 3/10 that is a fraction of 100:

$\dfrac{3}{10} = \dfrac{x}{100}\\\\\dfrac{300}{10}=x\\\\30 = x$

So 3/10 = 30/100 which in percentage form is 30%.

Now if:

17% = lions

30% = zebras

We can get the percentage by looking for how many out of 100% is left.

100% - (17% + 30%)

100% - 47%

53%

3 0

2 years ago

Complete the similarity statement for the two triangles shown. Enter your answer in the box. △XBR∼△ Two similar triangles B R X

Andreyy89

Answer:

Here, BRX and NJY are two triangles in which,

BR = 30 cm, RX = 40 cm, BX = 60 cm, NJ = 15 cm, JY = 20 cm and NY = 30 cm,

Also, m∠B = m∠N, m∠R = m∠J and m∠X = m∠Y,

By the property of congruence,

$\angle B \cong \angle N$ , $\angle R \cong \angle J$ and $\angle X \cong \angle Y$

Thus, By AAA similarity postulate,

$\triangle BRX\sim \triangle NJY$

Hence, proved.

5 0

2 years ago

When you divide a whole number by a decimal less than 1, the quotient is greater than the whole number. why?

Viktor [21]

Well if you get back to the definition of a division, diving X by Y is finding out how many Ys you can have in a X.

It is clear that you will have more than X times Y if Y is less than 1 since dividing X by 1 is exactly X.

If you think of 10 and 1, you can divide 10 in exactly 10 portions of 1.
But you can divide it into 100 portions of 0,1.
And 100 is bigger than 10 of course.
Hope this helps.

4 0

2 years ago

Read 2 more answers

Both copy machines reduce the dimensions of images that are run through the machines. Which

leonid [27]

<u>Answer:</u>

<u>As the number of copies increases The dimension of images continues to decrease until reaching 0. </u>

<u>Step-by-step explanation:</u>

Remember, that the term dimension refers not to an unlimited/unending length but to a specific measurable length.

Therefore, as both copy machines reduces the dimensions of images that are run through the machines over time the dimensions of images would decrease until reaching 0; Implying that the dimension is so small to be invisible, in a sense becoming 0.

3 0

2 years ago