Answer:
88.00 and subtract 28 and the 3 shirts were
Step-by-step explanation:
answer 60
Angles RLN and MLK would be vertical angles.
Right. Vertical angles are formed when their
sides share the same lines. RL shares the same line with LM and NL shares the
same line with LK (see the attached diagram), so that means both angles form a vertical
pair.
Angles RLN and MLN would be vertical angles.
Wrong. They are linear pairs, because they
are adjacent and supplementary. Adjacent angles share a side – in this case,
LN. Supplementary angles sum 180°, which you can see is right because the other
sides (ML and RL) are in the same line. RLN and MLN sum the same as the size of
RLM, which is a line, so it’s 180°.
<span>
Angles RLN and KLM would be a linear pair. </span>
Wrong. They would be a vertical pair (see
definition of vertical pair in the first option). RL is opposed to LM and LN is
opposed to KL.
Angles RLN and KLN would be a linear pair.
Wrong. KLN is actually a line, so it’s actually
180°, so it can’t be a linear pair with KLN. Linear pairs sum 180°, which is
impossible because KLN itself is already 180°, so any sum will throw a higher
number.
Answer:
2931 + 51.4n/7 degrees where n is the number of animal from the lion to the zebra in the clockwise direction.
Step-by-step explanation:
We don't have details on the positions of the lion and the zebra prior to revolution but suppose the zebra is n animal away from the lion where n could be in the range of 0 to 6 in the clockwise direction. If n = 0, the zebra is next to the lion in line, and if n = 6, the zebra is right behind the lion.
In angular term, since all 8 animals are evenly spaced, there are 7 space in between them, each of them would span an angle of 360/7 degrees
Then the angular distance between the zebra and the lion is (n+1)360/7 degrees
If the carousel makes between 8 and 9 revolutions then the total angular distance is 8*360 + (n+1)360/7 = 2931 + 51.4n/7 degrees
Check the picture below.
![\bf A=\cfrac{h(a+b)}{2}\quad \begin{cases} A=20\\ a=6z-1\\ b=2z+3\\ h=z \end{cases}\implies 20=\cfrac{z[(6z-1)~+~(2z+3)]}{2} \\\\\\ 20=\cfrac{z(8z+2)}{2}\implies 20=\cfrac{2z(4z+1)}{2}\implies 20=z(4z+1) \\\\\\ 20=4z^2+z\implies 0=4z^2+z-20](https://tex.z-dn.net/?f=%5Cbf%20A%3D%5Ccfrac%7Bh%28a%2Bb%29%7D%7B2%7D%5Cquad%20%0A%5Cbegin%7Bcases%7D%0AA%3D20%5C%5C%0Aa%3D6z-1%5C%5C%0Ab%3D2z%2B3%5C%5C%0Ah%3Dz%0A%5Cend%7Bcases%7D%5Cimplies%2020%3D%5Ccfrac%7Bz%5B%286z-1%29~%2B~%282z%2B3%29%5D%7D%7B2%7D%0A%5C%5C%5C%5C%5C%5C%0A20%3D%5Ccfrac%7Bz%288z%2B2%29%7D%7B2%7D%5Cimplies%2020%3D%5Ccfrac%7B2z%284z%2B1%29%7D%7B2%7D%5Cimplies%2020%3Dz%284z%2B1%29%0A%5C%5C%5C%5C%5C%5C%0A20%3D4z%5E2%2Bz%5Cimplies%200%3D4z%5E2%2Bz-20)

since the height is just a length unit, it can't be -2.3646.