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ANEK [815]
2 years ago
14

louise bought 80 metres of fencing to make an enclosure for her pet dog .tommy if louise expects a rectangular enclosure what is

the largest area it can have ? explain your answer​
Mathematics
1 answer:
OleMash [197]2 years ago
3 0

Answer:

400 m^2.

Step-by-step explanation:

The largest  area is obtained where the enclosure is a square.

I think that's the right answer because a square is a special form of a rectangle.

So the square would be 20 * 20  = 400 m^2.

Proof:

Let the  sides of the rectangle be x and y m long

The area A = xy.

Also the perimeter  2x + 2y = 80

x + y = 40

y = 40 - x.

So substituting for y in A = xy:-

A = x(40 - x)

A = 40x - x^2

For maximum value of A  we find the derivative and equate it to 0:

derivative A' =  40 - 2x = 0

2x = 40

x = 20.

So y = 40 - x

= 40 - 20

=20  

x and y are the same value so x = y.

Therefore for maximum area the rectangle is a square.

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2 years ago
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What is the length of AC ?<br><br> 3ft<br> 4ft<br> 9ft<br> 18ft
WINSTONCH [101]

ΔACB and ΔMNB are similar. Therefore the corresponding sides are in proportion:

\dfrac{AC}{MN}=\dfrac{CB}{NB}\\\\MN=9\ ft\\CB=2\cdot3\ ft=6\ ft\\NB=3\ ft

Substitute:

\dfrac{AC}{9}=\dfrac{6}{3}\\\\\dfrac{AC}{9}=2\ \ \ \ |\cdot9\\\\AC=18\ ft

5 0
2 years ago
The vertices of ΔRST are R(–1,–1), S(–1,11) and T(4,11). Which could be the side lengths of a triangle that is similar but not c
Step2247 [10]
The side lengths could be 10, 24 and 26 units.

We must first find the side lengths.  We use the distance formula to do this.

For RT:
d=\sqrt{(11--1)^2+(-1--1)^2}&#10;\\=\sqrt{(11+1)^2+(-1+1)^2}&#10;\\=\sqrt{12^2+0^2}=\sqrt{144}=12

For ST:
d=\sqrt{(11-11)^2+(4--1)^2}&#10;\\=\sqrt{0^2+(4+1)^2}=\sqrt{5^2}=\sqrt{25}=5

For TR:
d=\sqrt{(11--1)^2+(4--1)^2}&#10;\\=\sqrt{(11+1)^2+(4+1)^2}=\sqrt{12^2+5^2}=\sqrt{144+25}=\sqrt{169}=13

Our side lengths, from least to greatest, are 5, 12 and 13.

To be similar but not congruent, the side lengths must have the same ratio between corresponding sides but not be the same length.  10, 24 and 26 are all 2x the original side lengths, so this works.
5 0
2 years ago
An experiment was performed to compare the abrasive wear of two different laminated materials. Twelve pieces of material 1 were
vladimir1956 [14]

Answer:

The calculated value Z= 4.8389> 1.96 at 0.05 level of significance.

The null hypothesis is rejected.

There is  significance difference between that the abrasive wear of material 1 not exceeds that of material 2 by more than 2 units

Step-by-step explanation:

<u>Step:-(1)</u>

Given data the samples of material 1 gave an average (coded) wear of 85 units with a sample standard deviation of 4

Mean of the first sample x₁⁻ =85

standard deviation of the first sample S₁ = 4

Given data the samples of material 2 gave an average of 81 and a sample standard deviation of 5.

Mean of the first sample x₂⁻ =81

standard deviation of the first sample S₂ = 5

<u>Step :-2</u>

<u>Null hypothesis: H₀:</u> there is no significance difference between that the abrasive wear of material 1 exceeds that of material 2 by more than 2 units

<u>Alternative hypothesis :H₁: </u>there is  significance difference between that the abrasive wear of material 1 exceeds that of material 2 by more than 2 units

Assume the populations to be approximately normal with equal variances.σ₁² =σ₂²

The test statistic

                     Z= \frac{x_{1} -x_{2} }{\sqrt{\frac{S^2_{1} }{n_{1} } +\frac{S^2_{2} }{n_{2} }  } }

Given  n₁=n₂=60.

                    Z= \frac{85-81 }{\sqrt{\frac{(4)^2 }{60 } +\frac{5^2 }{60}  } }

On calculation, we get

                   Z =   \frac{4}{\sqrt{0.6833} }

                   z = 4.8389

The tabulated value Z =1.96 at 0.05 level of significance.

The calculated value Z= 4.8389> 1.96 at 0.05 level of significance.

The null hypothesis is rejected.

Conclusion:-

there is  significance difference between that the abrasive wear of material 1 not exceeds that of material 2 by more than 2 units.

3 0
2 years ago
14) Rounded to the nearest whole number, the square
Katen [24]

Answer:

3934

Step-by-step explanation:

Round 15,479,652 and find square root.

4 0
2 years ago
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