Simple :)
Area of shaded part = are of 1/4 circle - area of both triangles.
Are of circle = pie r^2 so 100x3.14 = 314 cm2.
Area of triangle AOB= area of triangleDOE = bh/2= 5x10/2= 25 each
However, the traingles share a common area which is quad DOB(I)
Lets take traingle AOE, whose are is bh/2=10x10/2=50cm2.
50-area of triangle A(I)E= 50-(
Answer:
21
Step-by-step explanation:
7.41 / 0.13 = 57
57 - 15 = 42
42 / 2 = 21
21, 36
we are given
DEF is a line
so, sum of angles must be 180
angle(DEG)+angle(GEF)=180
now, we can plug values
.........Answer
vertically opposite angle must be equal
angle(GEF)=angle(DEH)
now, we can plug values
now, we can plug x=16
...................Answer
Answer:
There is a correlation between age and length of stay. There may or may not be causation. Further studies would have to be done to determine this.
Step-by-step explanation:
The answer was checked
Answer:
The number of different combinations of three students that are possible is 35.
Step-by-step explanation:
Given that three out of seven students in the cafeteria line are chosen to answer a survey question.
The number of different combinations of three students that are possible is given as:
7C3 (read as 7 Combination 3)
xCy (x Combination y) is defines as
x!/(x-y)!y!
Where x! is read as x - factorial or factorial-x, and is defined as
x(x-1)(x-2)(x-3)...2×1.
Now,
7C3 = 7!/(7 - 3)!3!
= 7!/4!3!
= (7×6×5×4×3×2×1)/(4×3×2×1)(3×2×1)
= (7×6×5)/(3×2×1)
= 7×5
= 35
Therefore, the number of different combinations of three students that are possible is 35.
