Answer:
<em>c=6, d=2</em>
Step-by-step explanation:
<em>Equations
</em>
We must find the values of c and d that make the below equation be true
![\sqrt[3]{162x^cy^5}=3x^2y \sqrt[3]{6y^d}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B162x%5Ecy%5E5%7D%3D3x%5E2y%20%5Csqrt%5B3%5D%7B6y%5Ed%7D)
Let's cube both sides of the equation:
![\left (\sqrt[3]{162x^cy^5}\right )^3=\left (3x^2y \sqrt[3]{6y^d}\right)^3](https://tex.z-dn.net/?f=%5Cleft%20%28%5Csqrt%5B3%5D%7B162x%5Ecy%5E5%7D%5Cright%20%29%5E3%3D%5Cleft%20%283x%5E2y%20%5Csqrt%5B3%5D%7B6y%5Ed%7D%5Cright%29%5E3)
The left side just simplifies the cubic root with the cube:
![162x^cy^5=\left (3x^2y \sqrt[3]{6y^d}\right)^3](https://tex.z-dn.net/?f=162x%5Ecy%5E5%3D%5Cleft%20%283x%5E2y%20%5Csqrt%5B3%5D%7B6y%5Ed%7D%5Cright%29%5E3)
On the right side, we'll simplify the cubic root where possible and power what's outside of the root:

Simplifying

Equating the powers of x and y separately we find
c=6
5=3+d
d=2
The values are

Answer:
d
Step-by-step explanation:
when f(x)=5......It can also be
f(x)=1/125(625x)
every whole number over one...1(625x)=625x
also 125(1)=125 therefore (625/125)x=5x
A. 2¾ miles
b. 22 laps/hr
c. 12 laps
Answer:The amount of paint that was sold altogether is 173.36 litres
Step-by-step explanation:
The total amount of paint that the paint shop stocks is 1800 litres.
24% of the paint is white. It means that the amount of white paint would be
24/100 × 1800 = 0.24 × 1800 = 432 litres.
The amount of the remaining paint other than white would be
1800 - 432 = 1368 litres
The shops sells 18% of the white paint. This means that the amount of white paint sold by the shop will be
18/100 × 432 = 0.18 × 432 = 77.6 litres.
The shops sells 7% of the rest of the paint.
This means that the amount of the rest paint sold by the shop will be
7/100 × 1368 = 0.07 × 1368 = 95.76 litres.
The amount of paint that was sold altogether would be
77.6 + 95.76 = 173.36 litres
Answer:
The coordinates of EF are E(5,-4) and F(1,-4).
The line segment EF is in QIV
Step-by-step explanation:
The line segment AB has vertices at: A(-4,5) and B(-4,1).
We apply the rule
to reflect AB in the y-axis to obtain CD.


We apply the rule
to rotate CD 90 degrees clockwise about the origin to obtain EF.


The coordinates of EF are E(5,-4) and F(1,-4).
See attachment