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2 years ago

9

A sea turtle is 3 feet below the surface of the sea. If its position can be recorded as −3 feet, what would the position 0 repre

sent in this situation?

1 answer:

ArbitrLikvidat [17]2 years ago

7 0

The turtle is 3 feet below the surface of the sea, if it rises 3 feet, it will be even with sea level. So, 0 can be represented as sea level.

You might be interested in

Your drawer has 5 pairs of black socks, 4 pairs of gray socks, 2 pairs of white socks, 1 pair of brown socks, and 1 pair of blue

Sergeeva-Olga [200]

5 pairs of black socks*2 because it’s a pair= 10 socks
4 pairs of grey socks*2=8
2 pairs of white socks*2=4
1 pair of brown socks*2=2
1 pair of blue socks*2=2
10 socks+8 socks+4 socks+2 socks+ 2 socks=26 socks in total
26/2=13+1 because you need to be sure you get one pair of socks. The smallest amount of socks you would have to grab to get at least one matching pair is 14 socks.

7 0

2 years ago

The factory quality control department discovers that the conditional probability of making a manufacturing mistake in its preci

Anni [7]

Answer:

The probability that a defective ball bearing was manufactured on a Friday = 0.375

Step-by-step explanation:

Let the event of making a mistake = M

The event of making a precision ball bearing production on Monday = Mo

The event of making a precision ball bearing production on Tuesday = T

The event of making a precision ball bearing production on Wednesday = W

The event of making a precision ball bearing production on Thursday = Th

The event of making a precision ball bearing production on Friday = F

the conditional probability of making a manufacturing mistake in its precision ball bearing production is 4% on Tuesday, P(M|T) = 4% = 0.04

4% on Wednesday, P(M|W) = 0.04

4% on Thursday, P(M|Th) = 0.04

8% on Monday, P(M|Mo) = 0.08

and 12% on Friday = P(M|F) = 0.12

The Company manufactures an equal amount of ball bearings (20 %) on each weekday, Hence, the probability that a random precision ball bearing was made on a particular day of the week, is mostly the same for all the five working days.

P(Mo) = 0.20

P(T) = 0.20

P(W) = 0.20

P(Th) = 0.20

P(F) 0.20

The probability that a defective ball bearing was manufactured on a Friday = P(F|M)

P(F|M) = P(F n M) ÷ P(M)

P(F n M) = P(M n F)

P(M) = P(Mo n M) + P(T n M) + P(W n M) + P(Th n M) + P(F n M)

We can obtain each of these probabilities by using the expression for conditional probability.

P(Mo n M) = P(M|Mo) × P(Mo) = 0.08 × 0.20 = 0.016

P(T n M) = P(M|T) × P(T) = 0.04 × 0.20 = 0.008

P(W n M) = P(M|W) × P(W) = 0.04 × 0.20 = 0.008

P(Th n M) = P(M|Th) × P(Th) = 0.04 × 0.20 = 0.008

P(F n M) = P(M|F) × P(F) = 0.12 × 0.20 = 0.024

P(M) = P(Mo n M) + P(T n M) + P(W n M) + P(Th n M) + P(F n M)

P(M) = 0.016 + 0.008 + 0.008 + 0 008 + 0.024 = 0.064

P(F|M) = P(F n M) ÷ P(M)

P(F n M) = P(M n F) = 0.024

P(M) = 0.064

P(F|M) = P(F n M) ÷ P(M) = (0.024/0.064) = 0.375

Hope this Helps!

4 0

2 years ago

For which function does f decrease by 15% every time x increases by 1

LenaWriter [7]

Answer:

$f(x) = 0.85^{x}$

Step-by-step explanation:

The exponential function that decrease by 15% every time x increases by 1 is given by:

$f(x) = {(1 - 0.15)}^{x}$

We simplify the parenthesis to get:

$f(x) = 0.85^{x}$

Therefore the decrease by 15% every time x increases by 1 is

$f(x) = {0.85}^{x}$

The second choice is correct.

7 0

2 years ago

What additional information could you use to show that ΔSTU ≅ ΔVTU using SAS? Check all that apply.

GalinKa [24]

Options

A. UV = 14 ft and m∠TUV = 45°

B. TU = 26 ft

C. m∠STU = 37° and m∠VTU = 37°

D. ST = 20 ft, UV = 14 ft, and m∠UST = 98°

E. m∠UST = 98° and m ∠TUV = 45°

Answer:

A. UV = 14 ft and m∠TUV = 45°

D. ST = 20 ft, UV = 14 ft, and m∠UST = 98°

Step-by-step explanation:

Given

See attachment for triangle

Required

What proves that: ΔSTU ≅ ΔVTU using SAS

To prove their similarity, we must check the corresponding sides and angles of both triangles

First:

$\angle UST$ must equal $\angle UVT$

So:

$\angle UST = \angle UVT = 98$

Next:

UV must equal US.

So:

$UV = US = 14$

Also:

ST must equal VT

So:

$ST = VT = 20$

Lastly

$\angle TUV$ must equal $\angle TUS$

So:

$\angle TUV = \angle TUS = 45$

Hence: Options A and D are correct

4 0

2 years ago

The distribution of heights of a certain breed of terrier has a mean of 72 centimeters and a standard de- viation of 10 centimet

RSB [31]

Answer:

Pr(X-Y ≤ 44.2) = 0.5593

Step-by-step explanation:

for a certain breed of terrier

Mean(μ) = 72cm

Standard deviation (σ) = 10cm

n = 64

For a certain breed of poodle

Mean(μ) = 28cm

Standard deviation (σ) = 5cm

n = 100

Let X be the random variable for the height of a certain breed of terrier

Let Y be the random variable for the height of a certain breed of poodle

μx - μy = 72 -28

= 44

σx - σy = √(σx^2/nx + σy^2/ny)

= √10^2/64 + 5^2/100

= √100/64 + 25/100

= √ 1.8125

= 1.346

Using normal distribution,

Z= (X-Y- μx-y) / σx-y

Z= (44.2 - 44) / 1.346

Z= 0.2/1.346

Z= 0.1486

From the Z table, Z = 0.149 = 0.0593

Φ(z) = 0 0593

The probability that the difference of the observed sample mean is at most 44.3 is Pr(Z ≤ 44.2)

Recall that if Z is positive,

Pr(Z≤a) = 0.5 + Φ(z)

Pr(Z ≤ 44.2) = 0.5 + 0.0593

= 0.5593

Therefore,

Pr(X-Y ≤ 44.2) = 0.5593

5 0

2 years ago