Question

A rectangle has a height of w^2+3w+9w 2 +3w+9w, squared, plus, 3, w, plus, 9 and a width of w^2+2w 2 +2w, squared, plus, 2. Express the area of the entire rectangle.

Answer 1

Answer:

w⁴+5w³+17w²+24w +18

Step-by-step explanation:

Area of a rectangle = length * width

Given

Length  = w²+3w+9

width = w²+2w+2

Area of the rectangle = (w²+3w+9)(w²+2w+2)

Area of the rectangle = w²(w²) + 2w(w²) + 2w² + 3w(w²) + 3w(2w) + 2(3w)+9w²+9(2w)+9(2)

Area of the rectangle = w^4+2w^3+2w²+3w^3+6w^2+6w+9w²+18w+18

Collect the like terms;

Area of the rectangle = w^4+2w^3+3w^3+2w²+6w²+9w²+6w+18w+18

Area of the rectangle = w⁴+5w³+17w²+24w +18

Hence the area of the entire triangle is w⁴+5w³+17w²+24w +18