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RoseWind [281]
1 year ago
9

Pepper Corporation owns 75 percent of Salt Company's voting shares. During 20X8, Pepper produced 50,000 chairs at a cost of $79

each and sold 35,000 chairs to Salt for $90 each. Salt sold 18,000 of the chairs to unaffiliated companies for $117 each prior to December 31, 20X8, and sold the remainder in early 20X9 to unaffiliated companies for $130 each. Both companies use perpetual inventory systems. Based on the information given above, what amount of cost of goods sold must be reported in the consolidated income statement for 20X8?
a. $2,765,000
b. $1,620,000
c. $1,422,000
d. $2,963,000
Business
1 answer:
ludmilkaskok [199]1 year ago
5 0

Answer: c. $1,422,000

Explanation:

The Cost of Goods that goes into the Consolidated income statement would be the goods that were sold to unaffiliated companies. The original cost of production would apply:

= Quantity sold to unaffiliated companies in 20X8 * Cost for Pepper

= 18,000 * 79

= $1,422,000

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In the Vasquez Corporation, any overapplied or underapplied manufacturing overhead is closed out to Cost of Goods Sold. Last yea
wolverine [178]

Answer:

Cost of Goods Sold, after adjustment for overapplied manufacturing overhead, for the year must have been $69,000.

Explanation:

From the question, we have:

Applied manufacturing overhead cost = $29,000

Actual manufacturing overhead cost = $27,000

Cost of Goods Manufactured for the year = $71,000

Overapplied manufacturing overhead = Applied manufacturing overhead cost - Actual manufacturing overhead cost = $29,000 - $27,000 = $2,000

Therefore, we have:

Cost of Goods Sold = Cost of Goods Manufactured for the year - Overapplied manufacturing overhead = $71,000 - $2,000 = $69,000

Therefore, Cost of Goods Sold, after adjustment for overapplied manufacturing overhead, for the year must have been $69,000.

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2 years ago
Callista "cherry bomb" davidson is a world-famous stunt woman, and she is trying to achieve the long distance world record human
11Alexandr11 [23.1K]

Answer:

CODE

import time #importing time module

import math #importing math module

pi = math.pi #defining the value of pi

u = 70 #initial velocity

g = 9.8 #gravitational acceleration

time_step = 0.01 #time step of 0.01 secs

time_elapsed = 0.0

maxAngle = 0

angle = 1

h = 5.0 #setting the initial height to to 5m

x = 0.0

maxRange = 0.0

for angle in range(1,91): #loop which angle takes value from 1 to 90

ux = u * math.cos((pi / 180) * angle) #velocity in x axis

uy = u * math.sin((pi / 180) * angle) #velocity in y axis

for i in range(1000): #running for 1000 steps

dragx = 0.5 * 1.225 * 1.4 * 0.8 * ux * ux #calculating the drag in x direction

dragy = 0.5 * 1.225 * 1.4 * 0.8 * uy * uy #calculating the drag in y direction

drag_ax = dragx / 65.0 #calculating drag acceleration in x axis

drag_ay = dragy / 65.0 #calculating drag acceleration in y axis

accelx = drag_ax #resultant acceleration in x axis

accely = g + drag_ay #resultant acceleration in y axis

vx = ux - accelx * time_step #velocity in the x axis at any instant

vy = uy - accely * time_step #velocity in the y axis at any instant

h += uy * time_step - 0.5 * accely * time_step * time_step #height at any instant of the projectile

x += ux * time_step - 0.5 * accelx * time_step * time_step #range at any instant in the x axis of the projectile

print("Height " + str(h) + " Range " + str(x)) #printing the current position

time.sleep(time_step) #waiting for 0.01 secs

time_elapsed += time_step #calculating the time elapsed

ux = vx #setting the final velocitites to new initial velocities

uy = vy

if h <= 0.0: #if a height 0 is reached

if x > maxRange:

maxRange = x #max angles are noted

maxAngle = angle

h = 5.0 #variables are initialized

x = 0.0

u = 70.0

vx = 0.0

vy = 0.0

print("Wait till the next simulation starts.....")

time.sleep(10.0 - time_elapsed) #wait for 10 secs

time_elapsed = 0.0

break

print("The optimum angle for for Callista is {} degrees which will give her a range of {} metres".format(str(maxAngle),str(maxRange))) #the optimum angle is printed

Explanation:

3 0
2 years ago
Sherry's teacher told her that she should schedule an informational interview with the mayor of her city. Which two questions wo
tatiyna

Answer: Who else do you know in this career field that I could speak to about this career?

What experience did you obtain before being elected?

Explanation:

Informational interview is the interview which is conducted to obtain information from the celebrities, politicians, and other important people to understand and learn about the strategies and planning they are gone through with in their career.

Informational interview can also be defined as a kind of meeting in which the potential job seekers get career advice.

Here, Sherry is going to obtain the career advice from mayor. Thus she will ask question related to mayor's career.

She can ask about the prior experience of mayor in politics or any other field before he was elected. She can also ask about who else she can talk related to this career for better understanding.

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Explanation:

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You tapped on cell A1.

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2 years ago
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The correct answer is C.
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2 years ago
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