A rock climber is planning to climb a mountain cliff over two days. The climb begins at an altitude of 6,400 feet above sea leve
l. The rock climber figures
he can climb at an average pace of 360 feet per hour. He wants to climb to an altitude higher than 8,020 feet above sea level by the end of the first day of
climbing.
Which inequality and solution describe how many hours the climber must climb on the first day to reach his goal?
A
360h + 6,400 < 8,020, with a solution of h < 4
2
B
360h + 6,400 < 8,020, with a solution of h < 7
71
C
360h + 6,400 > 8,020, with a solution of h > 75
18
D
360h + 6,400 > 8,020, with a solution of h > 4.
2
he can climb at an average pace of 360 feet per hour. He wants to climb to an altitude higher than 8,020 feet above sea level by the end of the first day of
climbing.
Which inequality and solution describe how many hours the climber must climb on the first day to reach his goal?
A
360h + 6,400 < 8,020, with a solution of h < 4
2
B
360h + 6,400 < 8,020, with a solution of h < 7
71
C
360h + 6,400 > 8,020, with a solution of h > 75
18
D
360h + 6,400 > 8,020, with a solution of h > 4.
2
1 answer:
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Answer:
Step-by-step explanation:
we know that
The equation of the line into point slope form is equal to
In this problem we have
substitute the given values
therefore
y minus StartFraction one-third EndFraction equals StartFraction 3 Over 4 EndFraction left-parenthesis x minus 4 right-parenthesis.(x – 4)