Answer:Framed By Your Own Cells: How DNA Evidence Imprisons The Innocent ... But due to the touch-transfer properties of DNA, determining how those cells ... If we were to swab the man's hand for DNA, we might find the man's DNA, his ... Touch-transfer DNA "could falsely link someone to a crime" and forensic ...
Explanation:
Answer:
uniformitarianism, Fossil groups, 48 million years ago.
Explanation:
- Uniformitarianism is the doctrine of uniformity that assumes that same environmental laws and process operate till date that has also occurred on the past but not with the same uniformity. Unlike the atmospheric that is short-lived and sudden changes over the period of time.
- William Smith was a geologist who has noticed a certain type of fossil in a certain layer of sedimentary and igneous rock. A similar layer of strata could be found in the areas that were further apart.
- The Permian period was from 229 to 251 million years and was the last period of the paleozoic era and is recorded for the last major extinction in the history of life in earth and it lasted for 48 million years.
C is the answer because these accessory pigments on mass by the chlorophyll, which is responsible for producing food for the tree
Answer:
1) abiotic synthesis of small organic molecules (monomers)
2) joining of monomers into polymers
3) packaging of these molecules into protobionts, droplets with membranes that maintained a distinct internal chemistry
4) origin of self-replicating molecules that eventually made inheritance possible
Explanation:
Answer:
1. heterozygous yellow and star
2. 37
3. 1/8
4. 168
5. 1/4
Explanation:
Given ,
In f1 generation a cross is made between a true breeding black star bellied sneetch mated with a true breeding yellow starless sneetch
yySS x YYss
It is taken as - Y (yellow) is dominant over y (black)
and S (star) is dominant over s (starless)
1. F1 Generation
Genotype of parents yySS X YYss
gametes - yS, yS, Ys, Ys
All 16 offspring will have genotype YySs
phenotype would be heterozygous yellow and star
2. F2 generation cross
YySs X YySs
YS Ys yS ys
YS YYSS YYSs YySS YySy
Ys YYSs YYss YySs Yyss
yS YySS YySs yySS yySs
ys YySs Yyss yySs yyss
Genotype of offspring are –
YYSS – 1
YYSs – 2
YySS – 2
YySs – 4
YYss- 1
Yyss- 2
yySS – 1
yySs- 1
yyss- 1
2. Out of 16, 2 are black star bellied sneetches . Which means only 1/8 are black star bellied sneetches
So out of 300, 37 are black star bellied sneetches
3. Only 2 out of 16 are true breeding. i.e 1/8
4. 9 out of 16 are yellow star bellied sneetches, so out of 300, 168 are yellow star bellied sneetches
5. 4 out of 16 are true breeding yellow. Thus, ¼ are true breeding
