Hey hi your answer would be A<span> glycolysis </span>
Answer:
B. differential
Explanation:
The culture medium is a chemical preparation that has the necessary nutrients for microorganisms of a given biological sample to multiply, allowing its study, identification and analysis. The main components of a culture medium are sources of carbon, energy (sugars), nitrogen, phosphorus and minerals.
There are several types of culture medium, among them we can mention the differential culture medium, which is the type of medium that is being used in the experiment shown in the question above. The differential culture medium allows the distinction between various genera and species of similar microorganisms. This distinction is possible because this type of culture medium has substances that allow for a presumptive differentiation, evidenced by the color change or the morphology of the colonies.
<u>Phenylketonuria</u>
Explanation:
Phenylketonuria (PKU) is a type of a rare inherited metabolic disorder.
Etiology: PKU results from excessive accumulation of the amino acid phenylalanine in the body. Normally, phenylalanine will be converted to tyrosine (forms neurotransmitters) by the action of the enzyme phenylalanine hydroxylase.
Among people with PKU, a defect in the PAH gene which codes to synthesize this enzyme occurs which leads to the absence of this enzyme. So the phenylalanine which is normally present in dietary protein is not metabolized and gets accumulated. This gene is inherited by the child only if both the parents are with the defective PAH gene.
Symptoms: Stunted growth, behaviroral disturbances, learning difficulties, seizures, tremors etc.
Treatment: Basic treatment is to follow a diet which limits dietary sources of phenylalanine. High protein foods like meat, egg should be avoided. Children can be given PKU formula to supplement their nutritional needs.
Answer:
0.05 mg/mL ( B )
Explanation:
Given data:
20 mg/ml starch
2% solution = 2g of solute is in 100g of solvent
<u>Determine the new concentration in mg/ml </u>
Dilution equation = C1V1 = C2V2
new concentration ; applying the dilution factor
dilution factor = 1 : 400 ; ( 2 /400 )g = 0.005 g of solute is present in every 100 mL
∴ new concentration = 0.00005 g / 1 mL * ( 1000 mg / 1g ) = 0.05 mg/mL
