Answer: synthesize a pre-rRNA 45S (35S in yeast), which matures and will form the major RNA sections of the ribosome. RNA polymerase II synthesizes precursors of mRNAs and most snRNA and microRNAs. RNA polymerase III synthesizes tRNAs, rRNA 5S and other small RNAs found in the nucleus and cytosol.
Explanation:
Answer:
Approximately 12,500 SARS-CoV-2 viruses
Explanation:
According to this question, the period described is 1mm in diameter. Since 1millimetre(mm) is 1000metre(m), this means that the period is 0.001m in diameter.
Also, the SARS-CoV-2 virus has a diameter of 80 nm (1nm = 10^9m).
Since 10^6nanometres (nm) or 1,000,000nm makes 1millimeter (mm), 80nm of the virus will be:
= 80/1,000,000
= 0.000080mm or 8 × 10^-5mm
To calculate how many of the SARS-CoV-2 virus will fit into the period, we divide the diameter of the period (in mm) by the diameter of the virus (in mm).
That is; 1 ÷ 8 × 10^-5
= 1/8 × 10^5
= 0.125 × 100,000
= 12,500
Therefore, approximately 12500 SARS-CoV-2 viruses will fit in the period.
Answer:
characterized by presence or absence of antigens
the blood types are A, B, O, AB
Explanation:
There are two antigens and two antibodies that are mostly responsible for the ABO types. The specific combination of these four components determines an individual's type in most cases. Erythrocytes and serum were related to the presence of antigens on these erythrocytes and antibodies in the serum. these antigens are A and B, and depending upon which antigen the erythrocytes express, blood either belonged to blood group A or blood group B. A third blood group contained erythrocytes that reacted as if they lacked the properties of A and B, and this group was later called "O" blood group. The fourth blood group AB, was added to the ABO blood group system. These erythrocytes expressed both A and B antigens.
Blood group Antigen present on RBC Antibodies in serum Genotype(s)
A antigen A anti-B AA or AO
B antigen B anti-A BB or BO
AB both A and B antigen none AB
O none anti-A and anti-B OO