Answer:
The correct option is D. <u>The chemical bond breaks between the second and third phosphate groups.</u>
Explanation:
Adenosine phosphate (ATP) can be described as main energy-carrying molecules which are required by each cell to carry out its normal functions.
A molecule of ATP comprises of the nitrogenous base Adenine, pentose sugar ribose and three molecules of phosphate.
The bond between the second and third molecule carries high amounts of energy. When this bond is broken, huge amounts of energy is released which is used by the cells to carry out essential processes.
Answer:
The correct answer is - damaged, effector organ, neurilemma, damage, distance, cell body, decreased.
Explanation:
PNS axons are prone to cuts, and other types of injuries. A damaged axon can regenerate if the effector organ remains intact and a critical amount of neurilemma is found.
The degree of success of these axons regeneration depends upon factors that are (1) the amount of damage, and (2) the distance between the site of the damaged axon and the cell body it innervates The possibility of repair is reduced with an increase in either of these two factors. Neurolemmocytes play an active role in regeneration
Answer:
a) The response indicates that a pH below or above this range will most likely cause enolase to denature/change its shape and be less efficient or unable to catalyze the reaction.
b)The response indicates that the appropriate negative control is to measure the reaction rate (at the varying substrate concentrations) without any enzyme present.
c)The response indicated that the enolase has a more stable/functional/correct/normal protein structure at the higher temperature of 55°C than at 37°C because the enzyme is from an organism that is adapted to growth at 55°C.
Explanation:
Enolase catalyzes the conversion of 2-phosphoglycerate to phosphoenolpyruvate during both glycolysis and gluconeogenesis.In bacteria, enolases are highly conserved enzymes and commonly exist as homodimers.
The temperature optimum for enolase catalysis was 80°C, close to the measured thermal stability of the protein which was determined to be 75°C, while the pH optimum for enzyme activity was 6.5. The specific activities of purified enolase determined at 25 and 80°C were 147 and 300 U mg−1 of protein, respectively. Km values for the 2-phosphoglycerate/phosphoenolpyruvate reaction determined at 25 and 80°C were 0.16 and 0.03 mM, respectively. The Km values for Mg2+ binding at these temperatures were 2.5 and 1.9 mM, respectively.
Enolase-1 from Chloroflexus aurantiacus (EnoCa), a thermophilic green non-sulfur bacterium that grows photosynthetically under anaerobic conditions. The biochemical and structural properties of enolase from C. aurantiacus are consistent with this being thermally adapted.
Answer:
The best method of investigation that a scientist can use in an investigation of twins separated at birth - as in the case of Trinna and Suzanne - is a case study.
Explanation:
The case study is a qualitative research strategy that can be used in both biology, psychology and sociology, even combining these disciplines. Take an observed phenomenon, sometimes unique, looking for an explanation based on the examination and the elaboration of hypotheses.
Trinna, despite being an identical twin, developed a shorter stature and habits different from Suzanne, probably due to her growth in different environments.
The objective of the case study would be to demonstrate how the growth of twins in different settings may have caused physical and cultural differences in these identical twins.
Learn more:
Case study brainly.com/question/5167644
