Answer:
CPU need 50% much faster
disk need 100% much faster
Explanation:
given data
workload spend time CPU = 60%
workload spend time I/O = 40%
achieve overall system speedup = 25%
to find out
How much faster does CPU need and How much faster does the disk need
solution
we apply here Amdahl’s law for the overall speed of a computer that is express as
S =
.............................1
here f is fraction of work i.e 0.6 and S is overall speed i.e 100% + 25% = 125 % and k is speed up of component
so put all value in equation 1 we get
S =
1.25 =
solve we get
k = 1.5
so we can say CPU need 50% much faster
and
when f = 0.4 and S = 125 %
put the value in equation 1
S =
1.25 =
solve we get
k = 2
so here disk need 100% much faster
Answer:
1. It is so important for all application builders to always check data received from unknown sources before using that data. This is because of the Security related reasons and vulnerabilities .For example the data received might contain harmful hidden viruses. Web applications are accessed by internet and these are the most vulnerable to attacks by hacker or intruders using harmful data containing malware. This can cause security breaches due to the security flaws or bugs in Web applications. So to overcome such security risks which can cause damage in the Web applications, data from unknown sources should be checked.
Explanation:
2. When the Website is being used and running, there is a room for possible glitches or other bugs and issues. To understand, handle and address issues successfully, the website operators carefully and consistently patch and configure their systems. The administrators collect the user data which enables them to have enough data in order to make the requisite alterations or improvements in the website. This also helps to improve the website performance. The patching and configuring of systems fix problems in the website which reduces the risk of website damage and the website works smoothly this way. Moreover it identifies vulnerabilities, solve configuration issues and upgrades in website features provide additional capabilities to the website.
Answer:
For 32 bits Instruction Format:
OPCODE DR SR1 SR2 Unused bits
a) Minimum number of bits required to represent the OPCODE = 3 bits
There are 8 opcodes. Patterns required for these opcodes must be unique. For this purpose, take log base 2 of 8 and then ceil the result.
Ceil (log2 (8)) = 3
b) Minimum number of bits For Destination Register(DR) = 4 bits
There are 10 registers. For unique register values take log base 2 of 10 and then ceil the value. 4 bits are required for each register. Hence, DR, SR1 and SR2 all require 12 bits in all.
Ceil (log2 (10)) = 4
c) Maximum number of UNUSED bits in Instruction encoding = 17 bits
Total number of bits used = bits used for registers + bits used for OPCODE
= 12 + 3 = 15
Total number of bits for instruction format = 32
Maximum No. of Unused bits = 32 – 15 = 17 bits
OPCODE DR SR1 SR2 Unused bits
3 bits 4 bits 4 bits 4 bits 17 bits
Answer: Machine learning
Explanation:
The technology that could be combined with the current solution to do this is the machine learning.
Machine learning refers to the use and development of the computer systems which can learn and adapt without them following explicit instructions. This is done through the use of statistical models and algorithms in order to analyse inferences from the patterns in data.
Since the bank wants to streamline their operations for the receiving and processing checks while also enhancing the solution to recognize signs of potential check fraud, then the machine learning can be used.
Answer:
a) 10.53
b) 9.53
Explanation:
a) Average Turnaround Time: ( (8-0)+(12-0.4)+(13-1.0) ) / 3 = 10.53
b) Average Turnaround Time: ( (8-0)+(13-0.4)+(9-1.0) ) / 3 = 9.53