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ollegr [7]
1 year ago
13

When planning for a party, one caterer recommends the amount of meat be at least 2 pounds less than One-third the total number o

f guests. Which graph represents the overall equation represented by this scenario (all points may not apply to the scenario)?
Mathematics
1 answer:
makvit [3.9K]1 year ago
7 1
Drag the tiles to the correct boxes to complete the pairs. Not all tiles will be used.
Match each equation with its solution set.
a2 − 9a + 14 = 0
a2 + 9a + 14 = 0
a2 + 3a − 10 = 0
a2 + 5a − 14 = 0
a2 − 5a − 14 = 0
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How do you solve -9( -4r + 6s ) + 3s - 7(6s - 2r)
slavikrds [6]

Answer: 2.1 Pull out like factors :

6s - 2r  =   -2 • (r - 3s)

Equation at the end of step

 ((0-(9•(6s-4r)))+3s)--14•(r-3s)

Pulling out like terms

4.1     Pull out like factors :  6s - 4r  =   -2 • (2r - 3s)

Equation at the end of step

 ((0--18•(2r-3s))+3s)--14•(r-3s)

Final result :

 <u>50r - 93s</u>

7 0
2 years ago
For ΔABC, ∠A = 4x - 10, ∠B = 5x + 10, and ∠C = 7x + 20. If ΔABC undergoes a dilation by a scale factor of 1 3 to create ΔA'B'C'
VLD [36.1K]
We know that the angles of a triangle sum to 180°.  For ΔABC, this means we have:
(4x-10)+(5x+10)+(7x+20)=180

Combining like terms,
16x+20=180

Subtracting 20 from both sides:
16x=160

Dividing both sides by 16:
x=10
This means ∠A=4*10-10=40-10=30°; ∠B=5*10+10=50+10=60°; and ∠C=7*10+20=70+20=90.

For ΔA'B'C', we have
(2x+10)+(8x-20)+(10x-10)=180

Combining like terms, 
20x-20=180

Adding 20 to both sides:
20x=200

Dividing both sides by 20:
x=10

This gives us ∠A'=2*10+10=20+10=30°; ∠B'=8*10-20=80-20=60°; and ∠C'=10*10-10=100-10=90°.

Since the angle are all congruent, ΔABC~ΔA'B'C' by AAA.
5 0
2 years ago
Read 2 more answers
Marguerite is building a box from strips of wood she needs 78 pieces of wood that are 29 cm long the wood comes in boards that a
Morgarella [4.7K]
She bwill need 377 pices of wood hope this helps
3 0
2 years ago
[6+4=10 points] Problem 2. Suppose that there are k people in a party with the following PMF: • k = 5 with probability 1 4 • k =
kirza4 [7]

Answer:

1). 0.903547

2). 0.275617

Step-by-step explanation:

It is given :

K people in a party with the following :

i). k = 5 with the probability of $\frac{1}{4}$

ii). k = 10 with the probability of $\frac{1}{4}$

iii). k = 10 with the probability $\frac{1}{2}$

So the probability of at least two person out of the 'n' born people in same month is  = 1 - P (none of the n born in the same month)

= 1 - P (choosing the n different months out of 365 days) = 1-\frac{_{n}^{12}\textrm{P}}{12^2}

1). Hence P(at least 2 born in the same month)=P(k=5 and at least 2 born in the same month)+P(k=10 and at least 2 born in the same month)+P(k=15 and at least 2 born in the same month)

= \frac{1}{4}\times (1-\frac{_{5}^{12}\textrm{P}}{12^5})+\frac{1}{4}\times (1-\frac{_{10}^{12}\textrm{P}}{12^{10}})+\frac{1}{2}\times (1-\frac{_{15}^{12}\textrm{P}}{12^{15}})

= 0.25 \times 0.618056 + 0.25 \times 0.996132 + 0.5 \times 1

= 0.903547

2).P( k = 10|at least 2 share their birthday in same month)

=P(k=10 and at least 2 born in the same month)/P(at least 2 share their birthday in same month)

= $0.25 \times \frac{0.996132}{0.903547}$

= 0.0.275617

6 0
2 years ago
Is 9.42 a rational number
maksim [4K]
Yes because it can be put in a fraction and it ends

7 0
2 years ago
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