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ollegr [7]
1 year ago
13

When planning for a party, one caterer recommends the amount of meat be at least 2 pounds less than One-third the total number o

f guests. Which graph represents the overall equation represented by this scenario (all points may not apply to the scenario)?
Mathematics
1 answer:
makvit [3.9K]1 year ago
7 1
Drag the tiles to the correct boxes to complete the pairs. Not all tiles will be used.
Match each equation with its solution set.
a2 − 9a + 14 = 0
a2 + 9a + 14 = 0
a2 + 3a − 10 = 0
a2 + 5a − 14 = 0
a2 − 5a − 14 = 0
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The slope of the line below is -5/7 Write the point-slope equation of the line using the coordinates of the labeled point.
Vesna [10]

Answer:

The answer is C) y - 2 = -5/7(x - 6)

Step-by-step explanation:

Since we have the slope (-5/7) and a point (6, 2), we can just input those in for m and (x1, y1) in point-slope form.

y - y1 = m(x - x1)

y - 2 = -5/7(x - 6)

4 0
2 years ago
Read 2 more answers
The width of a rectangle is the length minus 3 units. The area of the rectangle is 54 units. What is the width, in units, of a r
saul85 [17]

Width of the rectangle is 9 units

Step-by-step explanation:

  • Step 1: Let the width of the rectangle be x. Then the length = x - 3. Find dimensions of the rectangle if its area = 54 sq. units

Area of the rectangle = length × width

54 = x (x - 3)

54 = x² - 3x

x² - 3x - 54 = 0

x² + 6x - 9x - 54 = 0 (Using Product Sum rule to factorize)

x(x + 6) - 9(x + 6) = 0

(x + 6)(x - 9) = 0

x = -6, 9 (negative value is neglected)

x = 9 units

4 0
2 years ago
On this map, Oxford Street is perpendicular to_______ , and Rosewood Street is perpendicular to ________. Assume that the street
melamori03 [73]
Hi there!

We are looking for perpendicular angles, which means the angle between the streets is 90 degrees. So, each time we need to find the street that intersects the given street with a 90 degree angle.

On this map, Oxford Street is perpendicular to Waterloo St., and Rosewood Street is perpendicular to Oak St..

The answers are (in correct order): Waterloo St. and Oak St..
~ Hope this helps you!
6 0
2 years ago
For a normally distributed random variable x with m = 75 and s = 4, find the probability that 69 < x < 79 Use the table to
nalin [4]

10-14-19-12-14-18-10-15-15

6 0
2 years ago
What is the horizontal asymptote for y(t) for the differential equation dy dt equals the product of 2 times y and the quantity 1
marta [7]
First, we need to solve the differential equation.
\frac{d}{dt}\left(y\right)=2y\left(1-\frac{y}{8}\right)
This a separable ODE. We can rewrite it like this:
-\frac{4}{y^2-8y}{dy}=dt
Now we integrate both sides.
\int \:-\frac{4}{y^2-8y}dy=\int \:dt
We get:
\frac{1}{2}\ln \left|\frac{y-4}{4}+1\right|-\frac{1}{2}\ln \left|\frac{y-4}{4}-1\right|=t+c_1
When we solve for y we get our solution:
y=\frac{8e^{c_1+2t}}{e^{c_1+2t}-1}
To find out if we have any horizontal asymptotes we must find the limits as x goes to infinity and minus infinity. 
It is easy to see that when x goes to minus infinity our function goes to zero.
When x goes to plus infinity we have the following:
$$\lim_{x\to\infty} f(x)$$=y=\frac{8e^{c_1+\infty}}{e^{c_1+\infty}-1} = 8
When you are calculating limits like this you always look at the fastest growing function in denominator and numerator and then act like they are constants. 
So our asymptote is at y=8.

3 0
1 year ago
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