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MrRa [10]
1 year ago
8

Your organization has an Active Directory domain. One of the users, Bill, should not have read access to a folder named Accounti

ng. The Accounting folder is shared on a network server, on a partition formatted as NTFS. Which of the following statements best describes how to stop Bill from having read access to the folder without impacting any other users on the network?
A. Remove Bill from all domain groups that have access to the Accounting folder.
B. Deny read access to the Accounting folder for Bill through local access security.
C. Deny read access to the Accounting folder for any group that Bill is a member of.
D. Deny read access to the Accounting folder for Bill through shared access security.
Computers and Technology
1 answer:
Alborosie1 year ago
5 0

Answer: D. Deny read access to the Accounting folder for Bill through shared access security.

Explanation:

The statement that describes how to stop Bill from having read access to the folder without impacting any other users on the network is to deny read access to the Accounting folder for Bill through shared access security.

It should be noted that the local access security cannot be used in this case because the folder is shared from a network server that is within the active directory domain.

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IANA has primarily been responsible with assigning address blocks to five regional internet registries (RIR). A tech needs to re
VikaD [51]

Answer:

The American Registry for Internet Numbers ARIN

Explanation:

The American Registry for Internet Numbers (ARIN) is a not for profit organization that serves as the administrator and distributor of Internet numeric resources such as IP addresses (IPv4 and IPv6) ASN for the United States, Canada, as well as North Atlantic and Caribbean islands

There are four other Regional Internet Registry including APNIC, RIPE NCC, LACNIC and AFRINIC.

6 0
1 year ago
A cyber criminal sends a series of maliciously formatted packets to the database server. The server cannot parse the packets and
telo118 [61]

Answer:

DoS attack

Explanation:

A Denial of Service attack involves the sending of maliciously formatted data packets to a server. The packet can be larger than the allowed IP size such that when it arrives at the server, the server cannot identify the headers in the data packet for it to process and extract data. The server can either freeze or crash, denying allowed users access to its resources and making it unavailable.

7 0
1 year ago
Generating a signature with RSA alone on a long message would be too slow (presumably using cipher block chaining). Suppose we c
boyakko [2]

Answer:

Following are the algorithm to this question:

Explanation:

In the RSA algorithm can be defined as follows:  

In this algorithm, we select two separate prime numbers that are the "P and Q", To protection purposes, both p and q combines are supposed to become dynamically chosen but must be similar in scale but 'unique in length' so render it easier to influence. Its value can be found by the main analysis effectively.  

Computing N = PQ.  

In this, N can be used for key pair, that is public and private together as the unit and the Length was its key length, normally is spoken bits. Measure,

\lambda (N) = \ lcm( \lambda  (P), \lambda (Q)) = \ lcm(P- 1, Q - 1)  where \lambda is the total function of Carmichaels. It is a privately held value. Selecting the integer E to be relatively prime from 1and gcd(E,  \lambda (N) ) = 1; that is E \ \ and  \ \ \lambda (N).  D was its complex number equivalent to E (modulo \lambda (N) ); that is d was its design multiplicative equivalent of E-1.  

It's more evident as a fix for d provided of DE ≡ 1 (modulo \lambda (N) ).E with an automatic warning latitude or little mass of bigging contribute most frequently to 216 + 1 = 65,537 more qualified encrypted data.

In some situations it's was shown that far lower E values (such as 3) are less stable.  

E is eligible as a supporter of the public key.  

D is retained as the personal supporter of its key.  

Its digital signature was its module N and the assistance for the community (or authentication). Its secret key includes that modulus N and coded (or decoding) sponsor D, that must be kept private. P, Q, and \lambda (N) will also be confined as they can be used in measuring D. The Euler totient operates \varphi (N) = (P-1)(Q - 1) however, could even, as mentioned throughout the initial RSA paper, have been used to compute the private exponent D rather than λ(N).

It applies because \varphi (N), which can always be split into  \lambda (N), and thus any D satisfying DE ≡ 1, it can also satisfy (mod  \lambda (N)). It works because \varphi (N), will always be divided by \varphi (N),. That d issue, in this case, measurement provides a result which is larger than necessary (i.e. D >   \lambda (N) ) for time - to - time). Many RSA frameworks assume notation are generated either by methodology, however, some concepts like fips, 186-4, may demand that D<   \lambda (N). if they use a private follower D, rather than by streamlined decoding method mostly based on a china rest theorem. Every sensitive "over-sized" exponential which does not cooperate may always be reduced to a shorter corresponding exponential by modulo  \lambda (N).

As there are common threads (P− 1) and (Q – 1) which are present throughout the N-1 = PQ-1 = (P -1)(Q - 1)+ (P-1) + (Q- 1)), it's also possible, if there are any, for all the common factors (P -1) \ \ \ and \ \ (Q - 1)to become very small, if necessary.  

Indication: Its original writers of RSA articles conduct their main age range by choosing E as a modular D-reverse (module \varphi (N)) multiplying. Because a low value (e.g. 65,537) is beneficial for E to improve the testing purpose, existing RSA implementation, such as PKCS#1, rather use E and compute D.

8 0
2 years ago
As the network administrator for a growing isp, you want to make efficient use of your network addresses. one of the network add
lubasha [3.4K]

New Subnet Mask:

255.255.255.240

First 4 subnetwork Addresses:

197.14.88.0

197.14.88.16

197.14.88.32

197.14.88.48

6 0
2 years ago
More Loops: All versions of foods.py in this section have avoided using for loops when printing to save space. Choose a version
Nata [24]

Answer:

Following are the program in the Python Programming Language.

#set list type variable and initialize the elements

myPizza = ['Margarita', 'Capsicum and onion', 'Chicken']

#set variable and initialize the elements

frndPizzas = myPizza[:]

#append value in list variable

myPizza.append('Corn')

#append value in list variable

frndPizzas.append('paperica')

#print message

print("My pizzas are:")

#set the for loop and print elements of 1st list

for pizza in myPizza:

   print(pizza)

#print message

print("\nFriend's pizzas are:")

#set the for loop and print elements of 2st list

for frndsPizza in frndPizzas:

   print(frndsPizza)

<u>Output</u>:

My pizzas are:                                                                                                                  

Margarita                                                                                                                       Capsicum and onion                                                                                                               Chicken                                                                                                                          Corn                                                                                                                                                                                                                                                        

Friend's pizzas are:                                                                                                            

Margarita                                                                                                                      Capsicum and onion                                                                                                              Chicken                                                                                                                         paperica    

Explanation:

<u>Following are the description of the program</u>:

  • Set a list data type variable that is 'myPizza' and initializes elements in it.
  • Set another list data type variable that is 'frndPizzas' and initializes elements in it.
  • Append one-one element in both of the list data type variables.
  • Set the for loops to print the elements of both list data type variables.
5 0
2 years ago
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