answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Kryger [21]
2 years ago
7

As the network administrator for a growing isp, you want to make efficient use of your network addresses. one of the network add

resses iana assigned to you is a class c network of 197.14.88.0. you have decided to use the addresses in this class c network to satisfy the ip address requirements of 16 corporate customers who need between 10 and 14 addresses each. calculate a subnet mask that meets their needs. list the subnet mask and the first four subnetwork addresses the mask will create.
Computers and Technology
1 answer:
lubasha [3.4K]2 years ago
6 0

New Subnet Mask:

255.255.255.240

First 4 subnetwork Addresses:

197.14.88.0

197.14.88.16

197.14.88.32

197.14.88.48

You might be interested in
Jefferson is interested in starting his own business. He plans to borrow money from the local bank in order to finance the busin
sweet [91]
A business plan and a <u>financial plan</u> to show the both his plan to make money, and how much money he will make, spend, use.
8 0
2 years ago
Read 2 more answers
Which Artificial Intelligence (AI) term is used to describe extracting information from unstructured text using algorithms?
Alla [95]

Answer:

The most basic and useful technique in NLP is extracting the entities in the text. It highlights the fundamental concepts and references in the text. Named entity recognition (NER) identifies entities such as people, locations, organizations, dates, etc. from the text.

5 0
2 years ago
1. A pure aggregator is best defined as a blog that
miss Akunina [59]
A pure aggregator is best defined as a blog that aggregates blog content from other sources.

An Aggregator blog or website don't write its own content. It aggregates information or content from third-party websites. There are different types of aggregator websites such as a poll aggregator, a review aggregator, and a search aggregator.
5 0
1 year ago
If you want more blank white space around the text in a document, you should increase the ____________.
Hatshy [7]

If you want more blank white space around the text in a document, you should increase the margin.  Correct answer: B

The margin is the area between the main content of a page (in this case that is the text) and the page edges. One-inch page margin is set automatically around each page. However,  you can customize or choose predefined margin settings.

3 0
2 years ago
Read 2 more answers
You have several pictures of different sizes that you would like to frame.A local picture framing store offers two types of fram
exis [7]

Answer:

written in java

Note :  Package name was excluded

 

import java.util.Scanner;

public class Main {

   public static void main(String[] args) {

       //declared 8 uninitialised variable  

       String input;

       double cost, colorC, frameC, paperC, glassC, crownC;

       char crowns;

       int type, color, crown, length, width, area, perimeter;

       

       //creating an instance of the Scanner class to accept value from user

       Scanner scanner = new Scanner(System.in);

       System.out.print("Enter length of frame: ");

       length = scanner.nextInt();

       System.out.print("Enter width of frame: ");

       width = scanner.nextInt();

       System.out.print("Do you want a fancy frame or a regular frame\nEnter 1 for fancy, 2 for regular: ");

       type = scanner.nextInt();

       if (type == 1) {

           frameC = 0.25;

       } else {

           frameC = 0.15;

       }

       System.out.print("Do you want a white frame or a colored frame\nEnter 1 for white, 2 for colored: ");

       color = scanner.nextInt();

       if (color == 2) {

           colorC = .10;

       } else{

           colorC = 0;

       }

       System.out.print("Do you want crowns \nEnter y for yes, n for no ");

       input = scanner.next();

       crowns = input.charAt(0);

       if (crowns == 'y' || crowns == 'Y') {

           System.out.print("How many crowns?");

           crown = scanner.nextInt();

       } else

           crown = 0;

       if (crown > 0)

           crownC = crown * .35;

       else

           crownC = 0;

       area = length * width;

       perimeter = length * 2 + width * 2;

       paperC = area * .02;

       glassC = area * .07;

       cost = glassC + paperC + crownC + colorC * perimeter + frameC * perimeter;

       System.out.println("The cost of your frame is: $" + cost);

   }

}

5 0
2 years ago
Other questions:
  • How frequently should computers containing ehr information be backed up?
    14·1 answer
  • Given a scanner reference variable named input that has been associated with an input source consisting of a sequence of strings
    14·2 answers
  • Edward has started up a new company with his friend, Matthew. Currently, he has only two people working with him. Which type of
    8·1 answer
  • Open this link after reading about Ana's situation. Complete each sentence using the drop-downs. Ana would need a minimum of ato
    5·2 answers
  • A remediation liaison makes sure all personnel are aware of and comply with an organization's policies.
    9·1 answer
  • Ciscon Telecom is a mobile operator in the European Union. The company provides personalized services to its customers, and its
    8·2 answers
  • The elements of an integer-valued array can be initialized so that a[i] == i in a recursive fashion as follows: An array of size
    10·1 answer
  • Exercise 3: Function Write a function named word_count that accepts a string as its parameter and returns the number of words in
    10·1 answer
  • [20 points] 3.3 Code Practice: Question 2
    7·1 answer
  • Which group contains the command to manually conduct a spell check ?
    9·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!