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Kryger [21]
2 years ago
7

As the network administrator for a growing isp, you want to make efficient use of your network addresses. one of the network add

resses iana assigned to you is a class c network of 197.14.88.0. you have decided to use the addresses in this class c network to satisfy the ip address requirements of 16 corporate customers who need between 10 and 14 addresses each. calculate a subnet mask that meets their needs. list the subnet mask and the first four subnetwork addresses the mask will create.
Computers and Technology
1 answer:
lubasha [3.4K]2 years ago
6 0

New Subnet Mask:

255.255.255.240

First 4 subnetwork Addresses:

197.14.88.0

197.14.88.16

197.14.88.32

197.14.88.48

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What kind of device can monitor a connection at the demarc but cannot interpret data?
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Answer: Smart jack

Explanation:

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2 Name the package that contains scanner class?​
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Which type of utp cable is used to connect a pc to a switch port?
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Which type of address is used at the transport layer to identify the receiving application?
monitta

Answer:

Port number  is used at the transport layer to identify the receiving application

Explanation:

Transport layer is responsible for overall “end-to-end” communication. It provides communication service to the application process which might be running on “different hosts”.

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5 0
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Write a program to declare a matrix A[][] of order (MXN) where ‘M’ is the number of rows and ‘N’ is the
Liula [17]

Answer:

import java.io.*;

import java.util.Arrays;

class Main {

   public static void main(String args[])

   throws IOException{

       // Set up keyboard input

       InputStreamReader in = new InputStreamReader(System.in);

       BufferedReader br = new BufferedReader(in);

 

       // Prompt for dimensions MxN of the matrix

       System.out.print("M = ");

       int m = Integer.parseInt(br.readLine());

       System.out.print("N = ");

       int n = Integer.parseInt(br.readLine());

       // Check if input is within bounds, exit if not

       if(m <= 2 || m >= 10 || n <= 2 || n >= 10){

           System.out.println("Matrix size out of range.");

           return;

       }

       // Declare the matrix as two-dimensional int array

       int a[][] = new int[m][n];

 

       // Prompt for values of the matrix elements

       System.out.println("Enter elements of matrix:");

       for(int i = 0; i < m; i++){

           for(int j = 0; j < n; j++){

               a[i][j] = Integer.parseInt(br.readLine());

           }

       }

       // Output the original matrix

       System.out.println("Original Matrix:");

       printMatrix(a);

       // Sort each row

       for(int i = 0; i < m; i++){

         Arrays.sort(a[i]);

       }

       // Print sorted matrix

       System.out.println("Matrix after sorting rows:");

       printMatrix(a);

   }

   // Print the matrix elements separated by tabs

   public static void printMatrix(int[][] a) {

       for(int i = 0; i < a.length; i++){

           for(int j = 0; j < a[i].length; j++)

               System.out.print(a[i][j] + "\t");

           System.out.println();

       }

   }

}

Explanation:

I fixed the mistake in the original code and put comments in to describe each section. The mistake was that the entire matrix was sorted, while only the individual rows needed to be sorted. This even simplifies the program. I also factored out a printMatrix() method because it is used twice.

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2 years ago
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