Answer:
The given coordinates of the vertices of rectangle ABCD are A(−2,2),B(4,2),C(4,−2).
We are to plot D on the graph.
Since ABCD is a rectangle, the abscissa of D will be that of A and the ordinate of D will be that of C.
Step-by-step explanation:
Answer:
Step-by-step explanation:
Given a sample M(t)
M(t) = 120 • ( 81 / 625)^t
When is the fraction of the mass decay to 3/5 of it's mass
Generally
M(t) = Mo•(k^t)
The original mass is 120
Mo = 120
So, we want to find time when it decay to 3/5 of it's original mas
M = 3/5 × 120
M = 72
Then,
M(t) = 120 • ( 81 / 625)^t
72 = 120 • ( 81 / 625)^t
72 / 120 = ( 81 / 625)^t
0.6 = ( 81 / 625)^t
Take natural logarithmic of both sides
In(0.6) = In(81/625)^t
In(0.6) = t•In(81/625)
t = In(0.6) / In(81/625)
t = In(0.6) / In(0.1296)
t = 0.25 monthly
t = ¼ monthly
Answer:
x^2 + (y – 3)^2 = 36
Step-by-step explanation:
The standard equation of a circle with center at (h, k) and radius r is
(x - h)^2 + (y - k)^2 = r^2.
If the center lies on the y-axis, then h = 0: (x - 0)^2 + (y - k)^2 = r^2
If the circle diameter is 12, then the circle radius is 6, and so r^2 = 36
So, among the given equations, your
x^2 + (y – 3)^2 = 36 is correct (but only if you use " ^ " for exponentiation).
Answer:

Step-by-step explanation:
You know that
and have to find

Use the main properties of exponents:
1. 
2. 
Note that

then

Now

Since
then 