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lys-0071 [83]
2 years ago
4

What is h(x) = –3x2 – 6x 5 written in vertex form? h(x) = –3(x 1)2 2 h(x) = –3(x 1)2 8 h(x) = –3(x – 3)2 – 4 h(x) = –3(x – 3)2 3

2
Mathematics
1 answer:
photoshop1234 [79]2 years ago
6 0
H(x) = –3(x + 1)2 + 8
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You are graphing rectangle ABCDABCDA, B, C, D in the coordinate plane. The following are three of the vertices of the rectangle:
vampirchik [111]

Answer:

The given coordinates of the vertices of rectangle ABCD are A(−2,2),B(4,2),C(4,−2).

We are to plot D on the graph.

Since ABCD is a rectangle, the abscissa of D will be that of A and the ordinate of D will be that of C.

Step-by-step explanation:

3 0
1 year ago
A sample of an unknown chemical element naturally loses its mass over time. The relationship between the elapsed time ttt, in mo
Naddik [55]

Answer:

Step-by-step explanation:

Given a sample M(t)

M(t) = 120 • ( 81 / 625)^t

When is the fraction of the mass decay to 3/5 of it's mass

Generally

M(t) = Mo•(k^t)

The original mass is 120

Mo = 120

So, we want to find time when it decay to 3/5 of it's original mas

M = 3/5 × 120

M = 72

Then,

M(t) = 120 • ( 81 / 625)^t

72 = 120 • ( 81 / 625)^t

72 / 120 = ( 81 / 625)^t

0.6 = ( 81 / 625)^t

Take natural logarithmic of both sides

In(0.6) = In(81/625)^t

In(0.6) = t•In(81/625)

t = In(0.6) / In(81/625)

t = In(0.6) / In(0.1296)

t = 0.25 monthly

t = ¼ monthly

6 0
2 years ago
Which equations represent circles that have a diameter of 12 units and a center that lies on the y-axis? Select two options. x2
olga55 [171]

Answer:

x^2 + (y – 3)^2 = 36

Step-by-step explanation:

The standard equation of a circle with center at (h, k) and radius r is

(x - h)^2 + (y - k)^2 = r^2.

If the center lies on the y-axis, then h = 0:  (x - 0)^2 + (y - k)^2 = r^2

If the circle diameter is 12, then the circle radius is 6, and so r^2 = 36

So, among the given equations, your

x^2 + (y – 3)^2 = 36 is correct (but only if you use " ^ " for exponentiation).

3 0
2 years ago
Read 2 more answers
If 3x-y=123x−y=123, x, minus, y, equals, 12, what is the value of \dfrac{8^x}{2^y} 2 y 8 x ​ start fraction, 8, start superscrip
julia-pushkina [17]

Answer:

2^{12}=4,096

Step-by-step explanation:

You know that 3x-y=12 and have to find

\dfrac{8^x}{2^y}

Use the main properties of exponents:

1. (a^m)^n=a^{m\cdot n}

2. \dfrac{a^m}{a^n}=a^{m-n}

Note that

8=2^3,

then

7^x=(2^3)^x=2^{3\cdot x}=2^{3x}

Now

\dfrac{8^x}{2^y}=\dfrac{2^{3x}}{2^y}=2^{3x-y}

Since 3x-y=12, then 2^{3x-y}=2^{12}=4,096

3 0
2 years ago
Read 2 more answers
Ethan deposited $198 in an account that earns 2.5% annual interest. He wants to buy a sound system that sells for $210. Will he
marishachu [46]
Yes he will have enough money.

5 0
2 years ago
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