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Alex_Xolod [135]
2 years ago
15

A taxi ride cost $2 for the first 1/5 of a km and 40 cents for each additional fifth of a km. Dan has $9.60. What is the longest

taxi ride he can afford, in kilometres?
Mathematics
1 answer:
Harlamova29_29 [7]2 years ago
5 0

Answer:

4 kilometers

Step-by-step explanation:

<em>First! Let's create an equation, with our variable (x) representing the number of additional fifth kilometers Dan can afford. </em>

2 + 0.40x = 9.60

<em>Now, we have to solve for our x value by subtracting 2 from both sides.</em>

0.40x = 7.60

<em>Next, we can divide both sides by 0.40 to find out what our x value is equal too.</em>

x = 19

<em>Don't forget this x value is just for the number of </em><em>additional</em><em> fifth kilometers Dan can afford on top of his first fifth mile.</em>

<em />

<em>So! Dan can afford 20 fifth kilometers, which in turn in is 4 kilometers in total. </em>

<em />

Hope this Helps! :)

<em>Have any questions? Ask below in the comments and I will try my best to answer.</em>

-SGO

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C_{52,5} = \frac{52!}{5!47!} = 2598960

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a.P(x)=\frac{n!}{x!(n-x)!}*p^{x}*(1-p)^{n-x}\\

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The probability that the company won x bids follows a binomial distribution because we have n identical and independent experiments with a probability p of success and (1-p) of fail.

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P(x)=\frac{n!}{x!(n-x)!}*p^{x}*(1-p)^{n-x}\\

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