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Vanyuwa [196]
2 years ago
7

Sandoval needs to determine its year-end inventory. The warehouse contains 26,000 units, of which 3,600 were damaged by flood an

d are not sellable. Another 2,600 units were purchased from Markor Company, FOB shipping point, and are currently in transit. The company also consigns goods and has 4,600 units at a consignee's location. How many units should Sandoval include in its year-end inventory?
a. 29,000.
b. 21,000.
c. 23,000.
d. 19,000.
e. 26,000.
Business
1 answer:
luda_lava [24]2 years ago
6 0

Answer:

the  number of units that should Sandoval include in its year-end inventory is 29,600 units

Explanation:

The computation of the number of units that should Sandoval include in its year-end inventory is given below:

= Opening units + units purchased + units at consignee location - units damaged

= 26,000 + 2,600 + 4,600 - 3,600

= 29,600

Hence, the  number of units that should Sandoval include in its year-end inventory is 29,600 units

This is the answer but the same is not provided in the given options

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Read 2 more answers
Redo the company’s income statement at the 5,000-unit level of activity using the contribution format.
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Using the high-low method, separate each mixed expense into variable and fixed elements. State the cost formula for each mixed expense. (Omit the "£" sign in your response.) 
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<span>Salaries and Commissions </span>
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<span>3. </span>
<span>Redo the company’s income statement at the 5,100-unit level of activity using the contribution format. (Input all amounts as positive values except losses which should be indicated by a minus sign. Omit the "£" sign in your response.) </span>

<span>Frankel Ltd. </span>
<span>Income Statement </span>
<span>For the Month Ended June 30 </span>
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<span>Cost of goods sold 346800 </span>
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7 0
1 year ago
Karen bought her house in 1980 for $78,500. In 2005, it was worth $850,000. What’s the rate of return on Karen’s investment?
motikmotik

Answer:

the rate of return on Karen investment is 10%

Explanation:

Given that

Bought price = P = $78500

Sale price = S =$850,000

Time priod = n = 25 years (1980 to 2005)

Based on the above information

The Rate of return is

= (S ÷ P)^(1 ÷ n) - 1

= ($850,000 ÷ $78,500)^(1 ÷ 25) - 1

= 0.099973

= 10.00%

hence, the rate of return on Karen investment is 10%

We simply applied the above formula

8 0
1 year ago
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