The area of a circle is 4π cm². What is the circumference, in centimeters? Express your answer in terms of \piπ.

The random variable X, representing the number of cherries in a cherry puff, has the following probability distribution:x: 4 - 5

marta [7]

Answer:

Step-by-step explanation:

Given is the probability distribution of a random variable X

X 4 5 6 7 Total

P 0.2 0.4 0.3 0.1 1

x*p 0.8 2 1.8 0.7 5.3

x^2*p 3.2 10 10.8 4.9 28.9

a) E(X) = Mean of X = sum of xp = 5.3

$Var(x) = 28.9-5.3^2=0.81$

Std dev = square root of variance = 0.9

------------------------------------

b) For sample mean we have

Mean = 5.3

Variance = var(x)/n = $\frac{0.81}{{36} } \\=0.0225$

c) $P(\bar X$

3 0

2 years ago

What is the volume of the pyramid?

s2008m [1.1K]

Answer:

$16\sqrt{3}$ $cm^{3}$

Step-by-step explanation:

I think your question missed key information, allow me to add in and hope it will fit the orginal one. Please have a look at the attached photo,

<em>A solid oblique pyramid has an equilateral triangle as a base with an edge length of 4StartRoot 3 EndRoot cm and an area of 12StartRoot 3 EndRoot cm2. </em>

<em>What is the volume of the pyramid?</em>

My answer:

As we know, The volume of a pyramid = $\frac{1}{3}$ base area × its height

Given:

Side lenght of the base is; $4\sqrt{3} cm$

=> The area of the base is $12\sqrt{3}$ $cm^{2}$

In Δ ACB measure of angle ACB is 90° and m∠ CAB is 30°

We use: $tan(30) = \frac{BC}{AC}$

<=> BC = $4\sqrt{3}*tan(30)$

= 4 cm

And BC is the height of the the pyramid

=> The volume of a pyramid = $\frac{1}{3}$ $12\sqrt{3}$ $cm^{2}$ * 4 cm

= $16\sqrt{3}$ $cm^{3}$

5 0

2 years ago

Read 2 more answers

A manager receives 8 applications for a specific position. She wants to narrow it down to 5. In how many ways can she rank 5 app

nata0808 [166]

Answer:

56 number of ways

Step-by-step explanation:

This question is a combination question since it involves selection.

Generally, if r objects are to be selected from n pool of objects, this can be done in nCr number of ways.

nCr = n!/(n-r)!r!

If a manager receives 8 applications for a specific position and wants to narrow it down to 5, the number of ways he can do this is 8C5

8C5 = 8!/(8-5)!5!

= 8!/3!5!

= 8*7*6*5!/3*2*5!

= 8*7*6/3*2

= 8*7

= 56 number of ways.

This means that the manager can rank 5 applications in 56 number of ways

7 0

2 years ago

In two or more complete sentences, compare the slopes of the two functions. In your comparison, include which function has the g

ziro4ka [17]

Answer:

I guess we have the table:

x f(x)

-4 7

-2 5

0 3

2 1

4 - 1

To find the slope of this, we need to select two different points (x1, y1) and (x2, y2) and use the relation:

slope = (y2 - y1)/(x2 - x1)

let´s use the first two:

(-4,7) and (-2, 5)

Slope = (5 - 7)/(-2 - (-4)) = -2/2 = -1

Now, if we want to be sure that this is a linear equation, we should do the same for other two pairs of points, now use the first and the third:

(-4, 7) and (0,3)

S = (3 - 7)/(0 -(-4)) = -4/4 = -1

Now, for the function g(x) we can see a constant line, that is parallel to the x-axis.

This means that the slope of this function is equal to zero.

This means that the slope of g(x) is bigger than the slope of f(x), because 0 > 1

6 0

2 years ago

The XO Group Inc. conducted a survey of 13,000 brides and grooms married in the United States and found that the average cost of

slavikrds [6]

Answer:

a) 0.0392

b) 0.4688

c) At least $39,070 to be among the 5% most expensive.

Step-by-step explanation:

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

$\mu = 29858, \sigma = 5600$