Answer:
![\frac{\sqrt[3]{16y^4}}{x^2}](https://tex.z-dn.net/?f=%5Cfrac%7B%5Csqrt%5B3%5D%7B16y%5E4%7D%7D%7Bx%5E2%7D)
Step-by-step explanation:
The options are missing; However, I'll simplify the given expression.
Given
![\frac{\sqrt[3]{32x^3y^6}}{\sqrt[3]{2x^9y^2} }](https://tex.z-dn.net/?f=%5Cfrac%7B%5Csqrt%5B3%5D%7B32x%5E3y%5E6%7D%7D%7B%5Csqrt%5B3%5D%7B2x%5E9y%5E2%7D%20%7D)
Required
Write Equivalent Expression
To solve this expression, we'll make use of laws of indices throughout.
From laws of indices ![\sqrt[n]{a} = a^{\frac{1}{n}}](https://tex.z-dn.net/?f=%5Csqrt%5Bn%5D%7Ba%7D%20%20%3D%20a%5E%7B%5Cfrac%7B1%7D%7Bn%7D%7D)
So,
gives

Also from laws of indices

So, the above expression can be further simplified to

Multiply the exponents gives

Substitute
for 32


From laws of indices

This law can be applied to the expression above;
becomes

Solve exponents


From laws of indices,
; So,
gives

The expression at the numerator can be combined to give

Lastly, From laws of indices,
; So,
becomes
![\frac{\sqrt[3]{(2y)}^{4}}{x^2}](https://tex.z-dn.net/?f=%5Cfrac%7B%5Csqrt%5B3%5D%7B%282y%29%7D%5E%7B4%7D%7D%7Bx%5E2%7D)
![\frac{\sqrt[3]{16y^4}}{x^2}](https://tex.z-dn.net/?f=%5Cfrac%7B%5Csqrt%5B3%5D%7B16y%5E4%7D%7D%7Bx%5E2%7D)
Hence,
is equivalent to ![\frac{\sqrt[3]{16y^4}}{x^2}](https://tex.z-dn.net/?f=%5Cfrac%7B%5Csqrt%5B3%5D%7B16y%5E4%7D%7D%7Bx%5E2%7D)
Answer:
Option C. The time in seconds that passed before the printer started printing pages
see the explanation
Step-by-step explanation:
Let
y ---->the number of pages printed.
x ---> the time (in seconds) since she sent a print job to the printer
we know that
The x-intercept is the value of x when the value of y is equal to zero
In the context of the problem
The x-intercept is the time in seconds that passed before the printer started printing pages (the number of pages printed is equal to zero)
In thermodynamics, specific volume is considered to be an
intrinsic property of matter. What we meant by intrinsic property is that, the
value of this property does not change no matter the size of the sample. This
is opposite to weight or volume which changes depending on the size of the
sample.
By mathematical definition, specific volume is the ratio of
the substance’s volume to its mass. Or in other words, this is the reciprocal
of density.
The formula for density is:
density = mass / volume
Since specific volume is reciprocal so:
Specific volume = 1 / density = volume / mass
Calculating:
Specific volume = 100 ft^3 / 5 pounds
Specific volume = 20 ft^3 / pound
Or when asked in units of m^3 / kg, we convert:
Specific volume = (20 ft^3 / pound) (2.2 pound / kg) (1 m^3
/ 35.3147 ft^3)
Specific volume = 1.246 m^3 / kg
Answer: 50%
Step-by-step explanation:
In 2010, there were only 2 bike manufacturers and they had market shares of 30% and 70%.
A new manufacturer joins the market and captures 10% of the market share and Splendor increases to 40% of market share.
Market shares:
Yamaha = 10%
Splendor = 40%
Passion = 100% - 10% - 40%
= 50%
Answer:
d
Step-by-step explanation:
when f(x)=5......It can also be
f(x)=1/125(625x)
every whole number over one...1(625x)=625x
also 125(1)=125 therefore (625/125)x=5x