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2 years ago

3. If p = 2q^2 - 5 and q = 10 - 3r, find r when p equals 67

Mathematics

2 answers:

xxMikexx [17]2 years ago

8 0

Answer:

Step-by-step explanation:

If p = 2q2 – 5 and q = 10 - 3r, find a. p when r equals 2 7. b. r when p equals 67. This problem has been solved!

Dvinal [7]2 years ago

8 0

Answer:

r = $\frac{4}{3}$

Step-by-step explanation:

When p = 67 , then

2q² - 5 = 67 ( add 5 to both sides )

2q² = 72 ( divide both sides by 2 )

q² = 36 ( take square root of both sides )

q = $\sqrt{36}$ = 6

Then

6 = 10 - 3r ( subtract 10 from both sides )

- 4 = - 3r ( divide both sides by - 3 )

$\frac{-4}{-3}$ = r , that is

r = $\frac{4}{3}$

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3. If p = 2q^2 - 5 and q = 10 - 3r, find r when p equals 67​

3. If p = 2q^2 - 5 and q = 10 - 3r, find r when p equals 67