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arsen [322]
2 years ago
14

A jar is filled with 1000 jelly beans . A random sample of 15 is taken from the jar and it is found to contain 2 black , 4 green

, 6 red , and the rest orange . Of the 1000 jelly beans in the jar. The expected number of black jelly beans and orange jelly beans respectively be :
A. 267,200
B. 257,300
C. 133,300
D. 133, 200​
Mathematics
2 answers:
Sergeeva-Olga [200]2 years ago
8 0

The answer would be B. 257,300

baherus [9]2 years ago
3 0
The answer to this would be d
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Troy made a scale drawing of the Statue of Liberty which has an actual height of 305 feet. He decides to use a scale in which 1
sergiy2304 [10]

The height of statue is 12.2 inches in Troy's drawing.

Step-by-step explanation:

Given,

Actual height of statue = 305 feet

Scale used by Troy;

25 feet = 1 inch

1 feet = \frac{1}{25}\ inches

305 feet = \frac{1}{25}*305 \ inches

305 feet = \frac{305}{25}\ inches\\

305 feet = 12.2 inches

The height of statue is 12.2 inches in Troy's drawing.

Keywords: unit rate, division

Learn more about unit rate at:

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#LearnwithBrainly

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2 years ago
Planes X and Y are perpendicular. Points A, E, F, and G are points only in plane X. Points R and S are points in both planes X a
motikmotik
Planes X and Y are perpendicular to each other
Points A, E, F, and G are points only in plane X
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The lines which could be perpendicular to RS are EA and FG.
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2 years ago
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Find the ratio of $22 to $5.50
solniwko [45]

Answer:

4:1

Step-by-step explanation:

22/5.50

divide numerator by denominator and denominator by denominator

22/5.50=4

5.50/5.50=1

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A carton of milk has spilled on a tile floor. The milk flow can be expressed with the function m(t) = 9t, where t represents tim
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Part A)     means that we have to find a composition of functions A and m
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part B)  
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Verify the given linear approximation at a = 0. Then determine the values of x for which the linear approximation is accurate to
nikklg [1K]

Answer:

Part 1)

See Below.

Part 2)

\displaystyle (-0.179, -0.178) \cup (-0.010, 0.012)

Step-by-step explanation:

Part 1)

The linear approximation <em>L</em> for a function <em>f</em> at the point <em>x</em> = <em>a</em> is given by:

\displaystyle L \approx f'(a)(x-a) + f(a)

We want to verify that the expression:

1-36x

Is the linear approximation for the function:

\displaystyle f(x) = \frac{1}{(1+9x)^4}

At <em>x</em> = 0.

So, find f'(x). We can use the chain rule:

\displaystyle f'(x) = -4(1+9x)^{-4-1}\cdot (9)

Simplify. Hence:

\displaystyle f'(x) = -\frac{36}{(1+9x)^{5}}

Then the slope of the linear approximation at <em>x</em> = 0 will be:

\displaystyle f'(1) = -\frac{36}{(1+9(0))^5} = -36

And the value of the function at <em>x</em> = 0 is:

\displaystyle f(0) = \frac{1}{(1+9(0))^4} = 1

Thus, the linear approximation will be:

\displaystyle L = (-36)(x-(0)) + 1 = 1 - 36x

Hence verified.

Part B)

We want to determine the values of <em>x</em> for which the linear approximation <em>L</em> is accurate to within 0.1.

In other words:

\displaystyle \left| f(x) - L(x) \right | \leq 0.1

By definition:

\displaystyle -0.1\leq f(x) - L(x) \leq 0.1

Therefore:

\displaystyle -0.1 \leq \left(\frac{1}{(1+9x)^4} \right) - (1-36x) \leq 0.1

We can solve this by using a graphing calculator. Please refer to the graph shown below.

We can see that the inequality is true (i.e. the graph is between <em>y</em> = 0.1 and <em>y</em> = -0.1) for <em>x</em> values between -0.179 and -0.178 as well as -0.010 and 0.012.

In interval notation:

\displaystyle (-0.179, -0.178) \cup (-0.010, 0.012)

4 0
2 years ago
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