Suppose you use the "capture/recapture" method to come up with an estimate of 200 fish living in a pond. Assume that this result
is accurate to within 20% of the estimate.
A. if P is the actual number of fish, write an inequality to describe the minimum number of fish in the pond.
B. Write an inequality to describe the maximum number of fish in the pond .
c. Combine your answers aboveinto a compound inequality.
A. if P is the actual number of fish, write an inequality to describe the minimum number of fish in the pond.
B. Write an inequality to describe the maximum number of fish in the pond .
c. Combine your answers aboveinto a compound inequality.
1 answer:
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Answer:
1. M=108
2. μ=110
3. In the explanation.
4. Test statistic t = -1.05
5. P-value = 0.1597
Step-by-step explanation:
The question is incomplete: to solve this problem, we need the sample information: size, mean and standard deviation.
We will assume a sample size of 10 matches, a sample mean of 108 points and a sample standard deviation of 6 points.
1. The mean points is the sample points and has a value of 108 points.
2. The null hypothesis is H0: μ=110, meaning that the mean score is not significantly less from 110 points.
3. This is a hypothesis test for the population mean.
The claim is that the mean score is significantly less than 110.
Then, the null and alternative hypothesis are:
The significance level is 0.05.
The sample has a size n=10.
The sample mean is M=108.
As the standard deviation of the population is not known, we estimate it with the sample standard deviation, that has a value of s=6.
The estimated standard error of the mean is computed using the formula:
4. Then, we can calculate the t-statistic as:
The degrees of freedom for this sample size are:
5. This test is a left-tailed test, with 9 degrees of freedom and t=-1.05, so the P-value for this test is calculated as (using a t-table):
As the P-value (0.1597) is bigger than the significance level (0.05), the effect is not significant.
The null hypothesis failed to be rejected.
There is not enough evidence to support the claim that the mean score is significantly less than 110.
Answer:
5 StartRoot 10 EndRoot
Step-by-step explanation:
we know that
The legs of a 45°-45°-90° triangle are congruent
Let
x ----> the length of one leg of the triangle
Applying the Pythagorean Theorem
where
c is the hypotenuse
a and b are the legs
we have
substitute
Simplify
5 StartRoot 10 EndRoot