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Mekhanik [1.2K]
1 year ago
6

A factory produces 125 bags of jelly beans every 10 seconds. Is there a linear function proportional? How do you know?

Mathematics
1 answer:
babunello [35]1 year ago
3 0
This problem is proportional! for every 1 second 12.5 jellybeans are made!
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Which of the following terms appear in the expansion of (x+y)^8? The letter a in each term represents a real constant.
Sedbober [7]

The given expression is

(x+y)^8

The exponent of x is decreasing and y in increasing .

That is ,

a x^8 +  b x^7y+ c x^6y^2 + d x^5 y ^3 + e x^4 y^4 + f x^3 y^5 + g x^2 y^6 +h x y^7 + i y^8

Where a,b,c,d,e,f,g,h,i are th constants

So the correct options are b and d .

5 0
2 years ago
Read 2 more answers
- Alisha had 3/4 yards of ribbon. She wanted to use it to decorate
Pachacha [2.7K]

Answer:

1/4 yards

Step-by-step explanation:

3/4 is the total. Divide the total by 3 to get the answer.

4 0
2 years ago
Meteorologists look for weather trends across US states in the same geographical region. Kentucky and Illinois share a border. T
olya-2409 [2.1K]

The average annual temperatures (°F) from 1991 to 2000 for Kentucky were 57.5, 55.1, 52.2, 55.6, 55.6, 54.4, 54.5, 58.3, 57.3, and 55.7.

We have to evaluate the measures of center.

Firstly, we will calculate the mean.

Mean = (Sum of all the observations)/ (Total number of observations)

Mean =  \frac{57.5+55.1+52.2+55.6+55.6+54.4+54.5+58.3+57.3+55.7}{10}

= \frac{556.2}{10}

= 55.62

Now, we will calculate mode.

Mode is a statistical term that refers to the most frequently occurring number found in a set of numbers.

Consider the data 57.5, 55.1, 52.2, 55.6, 55.6, 54.4, 54.5, 58.3, 57.3, and 55.7.

Mode = 55.6

Now, we will calculate the median.

Firstly, we will arrange in the ascending order.

52.2, 54.4, 54.4,55.1 ,55.6, 55.6, 55.7, 57.3, 57.5, 58.3

Since there are 10 terms.

Median = \frac{n}{2}th observation

Median = 5th observation.

Since, the 5th observation is 55.6.

Therefore, the median is 55.6

5 0
2 years ago
Read 2 more answers
A spotlight on the ground shines on a wall 12 m away. If a man 2 m tall walks along the x-axis from the spotlight toward the bui
Sedbober [7]

Answer:

0.675 m/s

Step-by-step explanation:

Let height of shadow= y,CD=x

Height of man=2 m

Speed of man= \frac{dx}{dt}=1. 8 m/s

\triangle ABD\sim\triangle ECD

Therefore, \frac{AB}{EC}=\frac{BD}{CD}

\frac{y}{2}=\frac{12}{x}

xy=24

Differentiate w.r.t t

x\frac{dy}{dt}+y\frac{dx}{dt}=0

x\frac{dy}{dt}=-y\frac{dx}{dt}

\frac{dy}{dt}=-\frac{y}{x}\frac{dx}{dt}

When the man is 4 m from  the building

Then, we have x=12-4=8 m

\frac{dx}{dt}=1.8 m/s

Substitute the values in above equation then, we get

8y=24

y=\frac{24}{8}=3

Substitute the values then we get

\frac{dy}{dt}=-\frac{3}{8}\times 1.8=-0.675 m/s

Hence, the length of his shadow on the building decreasing at the rate 0.675 m/s.

8 0
2 years ago
The area of a rectangle is 4w-10 square units. Factor this expression. Given your answer in part A, describe what you can conclu
vladimir2022 [97]

Answer:

length is 2 or 2w-5, and the width is 2w-5 or 2.

Step-by-step explanation:

common factor: 2

divide both by 2

4w/2=2w

10/2=5

(2w-5)

multiply by 2

2(2w-5)

the area of rectangle is l*w

the area of rectangle is 2(2w-5)

I can conclude that the length is 2 or 2w-5, and the width is 2w-5 or 2.

4 0
1 year ago
Read 2 more answers
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