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erma4kov [3.2K]
2 years ago
13

Which of the following terms appear in the expansion of (x+y)^8? The letter a in each term represents a real constant.

Mathematics
2 answers:
UkoKoshka [18]2 years ago
7 0

Answer: D. B.

Step-by-step explanation:

A P E X

Sedbober [7]2 years ago
5 0

The given expression is

(x+y)^8

The exponent of x is decreasing and y in increasing .

That is ,

a x^8 +  b x^7y+ c x^6y^2 + d x^5 y ^3 + e x^4 y^4 + f x^3 y^5 + g x^2 y^6 +h x y^7 + i y^8

Where a,b,c,d,e,f,g,h,i are th constants

So the correct options are b and d .

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A zookeeper predicted that the weight of a newborn lion would be 2.8 pounds. when the zoo's lion gave birth, the newborn weighed
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The sales data for January and February of a frozen yogurt shop are approximately normal. The mean daily sales for January was $
VashaNatasha [74]

Answer:

January had a higher z-score for sales on the 15th, and the value of that z-score was of 0.5.

Step-by-step explanation:

z-score:

In a set with mean \mu and standard deviation \sigma, the z-score of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

January:

The mean daily sales for January was $300 with a standard deviation of $20. On the 15th of January, the shop sold $310 of yogurt. This means, respectively, that \mu = 300, \sigma = 20, X = 310. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{310 - 300}{20}

Z = 0.5

February:

The mean daily sales for February was $320 with a standard deviation of $50. On the 15th of February, the shop sold $340 of yogurt. This means, respectively, that \mu = 320, \sigma = 50, X = 340. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{340 - 320}{50}

Z = 0.4

January had a higher z-score for sales on the 15th, and the value of that z-score was of 0.5.

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Lesson 3 homework practice mean absolute deviation
Natali5045456 [20]
Assuming that am supposed to calculate the the mean absolute deviation of 
1,2,3,4,5,6,7
mean absolute deviation is calculated by first calculating the mean;
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                               = 4
Then, find the absolute value (the difference between each value in the data and the mean) (x-μ)
 = -3,-2,-1,0,1,2,3
Absolute values= 3,2,1,0,1,2,3
Then we find the mean of the values,
3+2+1+0+1+2+3 = 12
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Therefore, the mean is 4, and the Mean absolute deviation is 1.7143
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