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2 years ago

Hamid is playing a trivia game with multiple choice questions. Each question has 2 correct answers among 5

Mathematics

2 answers:

goblinko [34]2 years ago

6 0

The probability that Hamid guesses both answers correctly is 10%.

Since Hamid is playing a trivia game with multiple choice questions, and each question has 2 correct answers among 5 answer choices, and Hamid has no idea what the answers to a certain question are, so he needs to choose two different answers at random, to determine what is the probability that Hamid guesses both answers correctly the following calculation must be performed:

2/5 x 1/4 = X
0.4 x 0.25 = X
0.1 = X
0.1 x 100 = 10

Therefore, the probability that Hamid guesses both answers correctly is 10%.

Learn more in brainly.com/question/22049333

NISA [10]2 years ago

5 0

Answer:

Step-by-step explanation:

khan

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Dapper Dan's Dancing School charges $85 for enrollment plus $6 per class, whereas Leaping Larry's Dancing School charges $40 for

gogolik [260]

Answer:

The Leaping Larry's Dancing School will be more expensive for a number of classes above 7.5 or equal to and above 8 classes

Step-by-step explanation:

The given information are;

The amount Dapper Dan's Dancing School charges for enrollment = $85

The amount Dapper Dan's Dancing School charges per class = $6

The amount Leaping Larry's Dancing School charges for enrollment = $40

The amount Leaping Larry's Dancing School charges per class = $12

Therefore, we have for X number of classes, when the cost of Dapper Dan's Dancing School and Leaping Larry's Dancing School are equal

$85 + X × $6 = $40 + X × $12

$85 - $40 = X × $12 - X × $6

$45 = X × $6

X = $45/$6 = 7.5

From which we have at X = 7.5 classes, the cost of the two dancing schools will be equal

However below 7.5 classes, for 7 classes for example, we have;

Cost of Dapper Dan's Dancing School = $85 + 7 × $6 = $127

Cost of Leaping Larry's Dancing School = $40 + 7 × $12 = $124

Therefore, for the number of classes below 7.5, Dapper Dan's Dancing School is more expensive than Leaping Larry's Dancing School

Above 7.5 classes, for 8 classes for example, we have;

Cost of Dapper Dan's Dancing School = $85 + 8 × $6 = $133

Cost of Leaping Larry's Dancing School = $40 + 8 × $12 = $136

Therefore, for the number of classes below 7.5, Dapper Dan's Dancing School is less expensive than Leaping Larry's Dancing School

Therefore, Leaping Larry's Dancing School will be more expensive for a number of classes above 7.5 or equal to and above 8 classes.

5 0

2 years ago

A common assumption in modeling drug assimilation is that the blood volume in a person is a single compartment that behaves like

mixas84 [53]

Answer:

a) $\mathbf{\dfrac{dx}{dt} = 30 - 0.015 x}$

b) $\mathbf{x = 2000 - 2000e^{-0.015t}}$

c) the steady state mass of the drug is 2000 mg

d) t ≅ 153.51 minutes

Step-by-step explanation:

From the given information;

At time t= 0

an intravenous line is inserted into a vein (into the tank) that carries a drug solution with a concentration of 500

The inflow rate is 0.06 L/min.

Assume the drug is quickly mixed thoroughly in the blood and that the volume of blood remains constant.

The objective of the question is to calculate the following :

a) Write an initial value problem that models the mass of the drug in the blood for t ≥ 0.

From above information given :

$Rate _{(in)}= 500 \ mg/L \times 0.06 \ L/min = 30 mg/min$

$Rate _{(out)}=\dfrac{x}{4} \ mg/L \times 0.06 \ L/min = 0.015x \ mg/min$

Therefore;

$\dfrac{dx}{dt} = Rate_{(in)} - Rate_{(out)}$

with respect to x(0) = 0

$\mathbf{\dfrac{dx}{dt} = 30 - 0.015 x}$

b) Solve the initial value problem and graph both the mass of the drug and the concentration of the drug.

$\dfrac{dx}{dt} = -0.015(x - 2000)$

$\dfrac{dx}{(x - 2000)} = -0.015 \times dt$

By Using Integration Method:

$ln(x - 2000) = -0.015t + C$

$x -2000 = Ce^{(-0.015t)$

$x = 2000 + Ce^{(-0.015t)}$

However; if x(0) = 0 ;

Then

C = -2000

Therefore

$\mathbf{x = 2000 - 2000e^{-0.015t}}$

c) What is the steady-state mass of the drug in the blood?

the steady-state mass of the drug in the blood when t = infinity

$\mathbf{x = 2000 - 2000e^{-0.015 \times \infty }}$

x = 2000 - 0

x = 2000

Thus; the steady state mass of the drug is 2000 mg

d) After how many minutes does the drug mass reach 90% of its stead-state level?

After 90% of its steady state level; the mas of the drug is 90% × 2000

= 0.9 × 2000

= 1800

Hence;

$\mathbf{1800 = 2000 - 2000e^{(-0.015t)}}$

$0.1 = e^{(-0.015t)$

$ln(0.1) = -0.015t$

$t = -\dfrac{In(0.1)}{0.015}$

t = 153.5056729

t ≅ 153.51 minutes

4 0

2 years ago

Use absolute value to express the distance between −10 and 16 on the number line.

Ede4ka [16]

I think 12,13,14 that's what I think

4 0

2 years ago

Read 2 more answers

PROBLEM SOLVING Scientists conducted aerial surveys of a seal sanctuary and recorded the number x of seals they observed during

Akimi4 [234]

Answer:

Probability that at most 50 seals were observed during a randomly chosen survey is 0.0516.

Step-by-step explanation:

We are given that Scientists conducted aerial surveys of a seal sanctuary and recorded the number x of seals they observed during each survey.

The numbers of seals observed were normally distributed with a mean of 73 seals and a standard deviation of 14.1 seals.

Let X = numbers of seals observed

The z score probability distribution for normal distribution is given by;

Z = $\frac{X-\mu}{\sigma}$ ~ N(0,1)

where, $\mu$ = population mean numbers of seals = 73

$\sigma$ = standard deviation = 14.1

Now, the probability that at most 50 seals were observed during a randomly chosen survey is given by = P(X $\leq$ 50 seals)

P(X $\leq$ 50) = P( $\frac{X-\mu}{\sigma}$ $\leq$ $\frac{50-73}{14.1}$ ) = P(Z $\leq$ -1.63) = 1 - P(Z < 1.63)

= 1 - 0.94845 = 0.0516

The above probability is calculated by looking at the value of x = 1.63 in the z table which has an area of 0.94845.

4 0

2 years ago

There are two pizzas. Conor ate 1⁄4 of a pizza, Brandon 2⁄8, Tyler 3⁄4, and Audrey 4⁄8. Who ate the most of the two pizzas?

Semenov [28]

Not exactly sure, but just by my knowledge and common sense I'd say Tyler. He ate 3/4 so he ate most out of what was given to him.

8 0

2 years ago