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Korvikt [17]
2 years ago
9

There are two pizzas. Conor ate 1⁄4 of a pizza, Brandon 2⁄8, Tyler 3⁄4, and Audrey 4⁄8. Who ate the most of the two pizzas?

Mathematics
1 answer:
Semenov [28]2 years ago
8 0
Not exactly sure, but just by my knowledge and common sense I'd say Tyler. He ate 3/4 so he ate most out of what was given to him. 
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A car travels 17 miles on one gallon of gas.
ehidna [41]

Answer:

y ranges from 2890 miles to 5780 miles.

Step-by-step explanation:

Let us call y the number of miles the car travels, and x the number of gallons of gas that are used, then we have the relationship

y=17x <em>(this says the car travels 17 miles for each gallon of gas).</em>

Now, when x=170, we have

y=17(170)

y=2890\: miles

and when x=340, we have

y=17(340)

y=5780\:miles

So, when x goes from 170 to 340, y goes from 2890 to 5780.

Therefore, when x ranges from 170  to 340 gallons, the distance traveled ranges from 2890 to 5780 miles.

5 0
2 years ago
Let C be the closed, piecewise smooth curve formed by traveling in straight lines between the points (-2,1), (-2,-3), (1,-1) , (
Greeley [361]

The given points are the vertices of the quadrilateral

Q=\left\{(x,y)\mid-2\le x\le1,\dfrac{2x-5}3\le y\le\dfrac{4x+11}3\right\}

By Green's theorem, the line integral is

\displaystyle\int_C2xy\,\mathrm dx+xy^2\,\mathrm dy=\iint_Q\frac{\partial(xy^2)}{\partial x}-\frac{\partial(2xy)}{\partial y}\,\mathrm dA

=\displaystyle\int_{-2}^1\int_{(2x-5)/3}^{(4x+11)/3}y^2-2x\,\mathrm dy\,\mathrm dx=\boxed{61}

6 0
2 years ago
An ostrich can run 6 mph faster than a giraffe. An ostrich can run 7 miles in the same time that a giraffe can run 6 miles. Find
LUCKY_DIMON [66]

NOTE THIS IS AN EXAMPLE:

Let t = time, s = ostrich, and g = giraffe.

Here's what we know:

s = g + 5 (an ostrich is 5 mph faster than a giraffe)

st = 7 (in a certain amount of time, an ostrich runs 7 miles)

gt = 6 (in the same time, a giraffe runs 6 miles)

 

We have a value for s, so plug it into the first equation:

(g + 5)t = 7

gt = 6

 

Isolate g so that we can plug that variable value into the equation:

g = 6/t

so that gives us:

(6/t + 5)t = 7

Distribute:

6 + 5t = 7

Subtract 6:

5t = 1

Divide by 5:

t = 1/5 of an hour (or 12 minutes)

 

Now that we have a value for time, we can plug them into our equations:

1/5 g = 6

multiply by 5:

g = 30 mph

 

s = 30 + 5

s = 35 mph

 

Check by imputing into the second equation:

st = 7

35 * 1/5 = 7

7 = 7

5 0
2 years ago
??? Really need help
Drupady [299]
A^2 + 5^2 = 10^2
a^2 + 25 = 100

a^2 = 100-25
a^2 = 75
a = sqrt(75) = 5sqrt(3)
 answer is A

3 0
2 years ago
HELP!!!!! This is due to DAy]
kompoz [17]

Answer:

D. 9

Step-by-step explanation:

9 is odd, however it is a composite number. That is the opposite of what the conditional is saying.

8 0
2 years ago
Read 2 more answers
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