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Travka [436]
2 years ago
8

A minister claims that more than 60% of the adult population attends a religious service at least once a month. The null and alt

ernative hypotheses you'd use to test this claim would be:
a. H0 : μ = .6, Ha: μ > .6
b. H0 : p = .6, Ha: p > .6
c. H0 : p = .6, Ha: p ≠ .6
d. H0 : pˆ = .6, Ha: pˆ > .6
e. H0 : x = .6, Ha: x > .6
Mathematics
1 answer:
LuckyWell [14K]2 years ago
6 0

Answer:

d. H0 : pˆ = .6, Ha: pˆ > .6

Step-by-step explanation:

Given that a minister claims that more than 60% of the adult population attends a religious service at least once a month.

Here the subject of interest about a proportion of adult population who attends a religious service at least once a month.

The claim is  this proportion is greater than 60% and we want to check  whether this claim is true.

Hence hypotheses would be for proportion only and not mean.

Since population proportion is to be checked we use p hat

Correct answer is

d. H0 : pˆ = .6, Ha: pˆ > .6

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stich3 [128]

Answer:

  (–1.4, 1.5)

Step-by-step explanation:

The blue line and the purple line are the lines corresponding to the equations of interest. Their point of intersection is in the 2nd quadrant, so is nearest to ...

  (–1.4, 1.5)

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It can be useful to understand that for equations in standard form:

  ax +by = c

the x- and y-intercepts are ...

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For the equations of interest, the first has intercepts of ...

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And the second has intercepts of ...

  x=-1, y=-4 . . . . graphed line makes a 3rd-quadrant triangle with the axes (purple line)

Since the purple line has a steeper slope, the point of intersection of the lines will be in the 2nd quadrant. There is only one 2nd-quadrant answer choice: (-1.4, 1.5).

5 0
2 years ago
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Our competitors struggled to sell 350 products last month and we sold 46% more than they did. How many more did we sell?
vekshin1
<span>Find out how much is 46% of 350 and add this number to 350 to get the number of products we sold. 46 % of 350 = 350 * 46/100 (46% is converted intro a fraction) = 161. The number of products we sold = 350 + 161 = 511</span>
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A principal of $2000 is placed in a savings account at 3% per annum compounded annually. How much is in the account after one ye
natita [175]

Answer:

Step-by-step explanation:

After one year

A=p(1+r/n)^nt

=2000(1+0.03/12)^12*1

=2000(1+0.0025)^12

=2000(1.0025)^12

=2000(1.0304)

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After two-years

A=p(1+r/n)^nt

=2060.8(1+0.03/12)^12*2

=2060.8(1+0.0025)^24

=2060.8(1.0025)^24

=2060.8(1.0618)

=$2188.157

After three years

A=p(1+r/n)^nt

=2188.157(1+0.03/12)^12*3

=2188.157(1+0.0025)^36

=2188.157(1.0025)^36

=2188.157(1.0941)

=$2394.063

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Which savings account can a financial institution end?
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<u>Answer:</u> Greta is correct.

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Greta is correct sine you can substitute different number of people for each of the values of and y and check that each person will still plant 4 trees.

For example:

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4 x 5 = 20

but you should follow a certain pattern to increase the value of x, such that every foe every value of x, one person is able to plant 4 trees.

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