Ask question

Ask question

All categories

2 years ago

9

In a fish tank, the ratio of goldfish to guppies is 2 to 4. There are a total of 12 fish in the fish tank. Determine the number

of goldfish in the fish tank.

1 answer:

miv72 [106K]2 years ago

7 0

4 goldfish 8 guppies

You might be interested in

Samuel and Hayden solved the system of equations –6x – 6y = –6 and 7x + 7y = 7. Samuel says there are infinitely many solutions,

yawa3891 [41]

Answer:

Samuel is correct i.e there are infinitely many solutions

Step-by-step explanation:

Given that Samuel and Hayden solved the system of equations –6x – 6y = –6 and 7x + 7y = 7. we have to find that whether the system of equations has infinitely many solutions or not.

A system of linear equations has infinite solutions if the graphs are the exact same line i.e the the equations are equivalent.

The first equation: –6x – 6y = –6 ⇒ x+y=1 ⇒ y=-x+1

∴ the slope of its line is -1 and the y-intercept is 1

The second equation: 7x + 7y = 7 ⇒ x+y=1 ⇒ y=-x+1

∴ the slope of its line is -1 and the y-intercept is 1.

Here, we get the equation which has the same slope and y-intercept as that of the first equation.

In other words, the two equations are represented by the same line. This implies that the lines intersect infinitely many times, or that the system has infinitely many solutions.

Hence, Samuel is correct.

7 0

2 years ago

Read 2 more answers

Let Î be a Bernoulli random variable that indicates which one of two hypotheses is true, and let P(Î = 1) = p. Under the hypothe

Natasha_Volkova [10]

I am so confused on this can u help me

5 0

2 years ago

Tiffany buys a basket of watermelons on sale for \$9$9dollar sign, 9 before tax. The sales tax is 9\%9%9, percent. What is the t

vladimir2022 [97]

Given that the basket of watermelons sells for $9 before tax and the tax rate is 9%.

The tax on the basket of watermelons is given by

$\frac{9\%}{100\%} \times\$9=0.09\times\$9 \\ \\ =\$0.81$

Therefore, the total price Tiffany pays for the basket of watermelons is $9 + $0.81 = $9.81

8 0

2 years ago

Read 3 more answers

A clothing store is analyzing merchandise prices to help make decisions on what to charge for clothing on clearance. The store o

Aleks [24]

The variable is Quantitative, has Interval level of measurement.

Variables which can be quantified & expressed numerically are Quantitative variables. Eg : as given , price

Variables which cant be qualified & expressed numerically are Qualitative variables. Eg : level of honesty, loyalty etc

Nominal & Ordinal are qualitative variables : signifying yes or no to a category (like men or women) , or ranks (x better than y) respectively. So price level is not such categorical & ordinal ratio.

Quantitative ratio variables are with reference to time , or are in forms of rate (like speed , growth per year). So, price level is not such ratio variable also.

Price is a quantitative variable, in which the ranking, its difference can be calculated. This is characteristic of a <u>Quantitative Interval Variable</u>.

4 0

2 years ago

The area of ABED is 49 square units. Given AGequals9 units and ACequals10 units, what fraction of the area of ACIG is represent

Mrac [35]

Answer:

The fraction of the area of ACIG represented by the shaped region is 7/18

Step-by-step explanation:

see the attached figure to better understand the problem

step 1

In the square ABED find the length side of the square

we know that

AB=BE=ED=AD

The area of s square is

$A=b^{2}$

where b is the length side of the square

we have

$A=49\ units^2$

substitute

$49=b^{2}$

$b=7\ units$

therefore

$AB=BE=ED=AD=7\ units$

step 2

Find the area of ACIG

The area of rectangle ACIG is equal to

$A=(AC)(AG)$

substitute the given values

$A=(9)(10)=90\ units^2$

step 3

Find the area of shaded rectangle DEHG

The area of rectangle DEHG is equal to

$A=(DE)(DG)$

we have $DE=7\ units$

$DG=AG-AD=9-7=2\ units$

substitute $A=(7)(2)=14\ units^2$

step 4

Find the area of shaded rectangle BCFE

The area of rectangle BCFE is equal to

$A=(EF)(CF)$

we have

$EF=AC-AB=10-7=3\ units$

$CF=BE=7\ units$

substitute

$A=(3)(7)=21\ units^2$

step 5

sum the shaded areas

$14+21=35\ units^2$

step 6

Divide the area of of the shaded region by the area of ACIG

$\frac{35}{90}$

Simplify

Divide by 5 both numerator and denominator

$\frac{7}{18}$

therefore

The fraction of the area of ACIG represented by the shaped region is 7/18

5 0

2 years ago