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suter [353]
2 years ago
6

Let Î be a Bernoulli random variable that indicates which one of two hypotheses is true, and let P(Î = 1) = p. Under the hypothe

sis Î = 0, the random variable X is uniformly distributed over the interval [0,1]. Under the alternative hypothesis Î = 1, the PDF of X is given by fX| Î(x|1) = 2x if 0<=x<=1 and 0 otherwise. Consider the MAP rule for deciding between the two hypotheses, given that X=x. Find the probability of error associated with the MAP rule as a function of p.
Mathematics
1 answer:
Natasha_Volkova [10]2 years ago
5 0
I am so confused on this can u help me
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Kaitlyn solved the equation for x using the following calculations. Negative 5.4 + x = 12.2. Minus 5.4. x = 6.8. What error, if
omeli [17]

Step-by-step explanation:

The equation that Kaitlyn solved is as follows :

-5.4+x=12.2

The steps to solve it as follows :

Step 1. Add 5.4 to both sides,

-5.4+x+5.4=12.2+5.4

Step 2. 5.4 will cancel out as both have opposite signs

x=17.6

But Kaitlyn solved it as :

5.4.x=6.8

She has multiplied -5.4 and x which is wrong. The correct answer is 17.6.

3 0
2 years ago
The entire universe of computer games are made up of:
expeople1 [14]

Answer:

Math properties the programmer had put into the software. The majority of programming software is based in math.

Step-by-step explanation:

The other 3 possible answers make no sense.

1. Pixels with red, green, and blue switches - Seriously???

2. Code randomly created by programmers - Seriously???

3. The fundamental properties of physics which consist of numbers and constants (numbers and constants are the same thing and physics has virtually nothing to do with programming)

4 0
2 years ago
Find the number a such that the line x = a bisects the area under the curve y = 1/x2 for 1 ≤ x ≤ 4. 8 5​ (b) find the number b s
IceJOKER [234]

a. We're looking for a such that

\displaystyle\int_1^a\frac{\mathrm dx}{x^2}=\int_a^4\frac{\mathrm dx}{x^2}

-\dfrac1x\bigg|_{x=1}^{x=a}=-\dfrac1x\bigg|_{x=a}^{x=4}

1-\dfrac1a=\dfrac1a-\dfrac14

\dfrac54=\dfrac2a\implies\boxed{a=\dfrac85}

b. Integrating with respect to y will make things easier.

y=\dfrac1{x^2}\implies x=\dfrac1{\sqrt y}

(where we take the positive square root because we know x>0)

Now we want to find b such that

\displaystyle\int_0^b\frac{\mathrm dy}{\sqrt y}=\int_b^1\frac{\mathrm dy}{\sqrt y}

2\sqrt y\bigg|_{y=0}^{y=b}=2\sqrt y\bigg|_{y=b}^{b=1}

2\sqrt b=2-2\sqrt b

4\sqrt b=2\implies\boxed{b=\dfrac14}

3 0
2 years ago
A sphere has a diameter of 22 units what is the radius and volume
lilavasa [31]

Answer:


Step-by-step explanation:

11

7 0
2 years ago
Rotate : energy :: stop:
vitfil [10]
Is that a question???????
4 0
2 years ago
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