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zalisa [80]
2 years ago
10

Megan and Suzanne each have a plant. They track the growth of there plants for four weeks. Whos plant grew at a faster rate, and

what was the rate
Mathematics
2 answers:
il63 [147K]2 years ago
3 0
In order for this question to be answered, you need to state how much each plant grew. Otherwise, the brainly user won't have anything to work with.
zavuch27 [327]2 years ago
3 0

Answer:

D. Megan’s at 2.5 inches per week

Hope this helps

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Estimate 58% of 121 by using 10%
kvv77 [185]
58% is about equal to 60%, 10% of 121 is 12.1.
12.1 * 6 = 72.6
To take this further, 58% is 2% less than 60%, or 2 times 1%. 1% of 121 is 1.21.
72.6  - (1.21 * 2) = 72.6 - 2.42 = 70.18
5 0
2 years ago
Maya had $27. She spent all the money on buying 3 burgers for $x each and 2 sandwiches for $y each. If Maya had bought 2 burgers
Ber [7]
Let
x-------> the cost of the burger
y-------> the cost of the <span>sandwiches

we know that
3x+2y=27-----> equation 1
2x+y=27-11-----> 2x+y=16-----> multiply by -2-----> -4x-2y=-32--> equation 2

adds equation 1 and equation 2
</span> 3x+2y=27
-4x-2y=-32
<span>----------------
-x=27-32-----> x=5
3*5+2y=27----> 2y=27-15-----> y=6

therefore

the answer is the option
</span><span>3) The student's conclusion is correct because the solution to the system of equations 3x + 2y = 27 and 2x + y = 16 is (5, 6).</span>
3 0
2 years ago
PLEASE HELP MATH EXPAND LOG
blsea [12.9K]

Answer:

½log3 + ½logx

Step-by-step explanation:

½(log(3x))

½(log3 + logx)

½logx + ½log3

8 0
2 years ago
Makayla has $8 to buy tickets at the school fair. Each ticket costs @1.5. Which inequality best represents how many tickets she
cricket20 [7]

Answer:

n\le 5

Step-by-step explanation:

Let n be the number of tickets Makaya has to buy.

If the cost of one ticket is $1.5, then the cost of n tickets is $1.5n.

Makayla has $8 to buy tickets at the school fair, thus

1.5n\le 8\\ \\n\le \dfrac{8}{1.5}\\ \\n\le \dfrac{80}{15}\\ \\n\le \dfrac{16}{3}\\ \\n\le 5\dfrac{2}{3}

The maximum number of tickets Makaya can buy is 5, so

n\le 5

5 0
2 years ago
The population p of a small community on the outskirts of a city grows rapidly over a 20-year period: t05101520p1002004509502000
myrzilka [38]

Answer:

The population of the small community, 5 years into the future, after the initial 20-year period = 4268.

Step-by-step explanation:

t | 0 | 5 | 10 | 15 | 20

p | 100 | 200 | 450 | 950 | 2000

The exponential function will look like

p = aeᵏᵗ

where a and k are constants.

Take the natural logarithms of both sides

In p = In aeᵏᵗ

In p = In a + In eᵏᵗ

In p = In a + kt

In p = kt + In a.

We then use linear regression to fit the data of In p against t to obtain k and In a.

t | 0 | 5 | 10 | 15 | 20

p | 100 | 200 | 450 | 950 | 2000

In p | 4.605 | 5.298 | 6.109 | 6.856 | 7.601

In p = kt + In a.

y = mx + b

m = k and b = In a

Performing a linear regression analysis on the now-linear relationship between In p and t and also plotting a graph of the variables.

The regression equation obtained is

y = 0.151x + 4.584

The first attached image shows the equations necessary for the estimation of the linear regression parameters.

The second attached image shows the use of regression calculator and the plot of the function In p versus t.

Comparing

y = 0.151x + 4.584

With

In p = kt + In a.

y = In p

k = 0.151

x = t

In a = 4.584

a = 97.905

The exponential function relating p and t,

p = aeᵏᵗ now becomes

p = 97.905 e⁰•¹⁵¹ᵗ

So, to predict the population 5 years into the future, that is 5 years after the 20 year period.

we need p at t=25 years.

0.151 × 25 = 3.775

p(t=25) = 97.905 e³•⁷⁷⁵ = 4268.41 = 4268.

Hope this Helps!!!

7 0
2 years ago
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