Here are the equations
x+y=48
x/y=5/8
but here's how I would solve it
5+7=12
48=12units
divide by 12 both sides
4=1unit
males=5 unit
4=1unit
times 5
20=5unit=males
females=7unit
4=1unit
times 7
28=7unit=females
The answer to the problem is as follows:
Count all boys as one unit. Then there is one boy and 2 girls who can be permuted in 3! = 6 ways. Bout the 3 boys can permute among themselves in 3! = 6 ways.
<span>6x6 = 36 ways in which all boys are together.
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I hope my answer has come to your help. God bless and have a nice day ahead!
-7x+4 i’m not sure if it’s correct but i hope it is. sorry if it’s not
<span>Amanda has 26 nickels and dimes.
We shall call nickels x and dimes y.
We can write the following equations:
x = 3y -2 or -x +3y = 2
x + y = 26
We can cancel out the x to give 4y = 28 or y = 7
If there are 26 coins in total and 7 of them are dimes then there must be 19 nickels.
The number of nickels (19) is two fewer than three times the number of dimes ( 3(7) - 2 = 19).</span>
Answer:
C
Step-by-step explanation:
Stay safe hope this helps