Question

A theater production group is making frames to support wall-like props. Three-foot beams form right triangles with 10-foot beams to allow them to stand, as shown in the image.
What is x, the angle at which the diagonal beam meets the 10-foot beam at the top of the frame?
16.7°
17.5°
72.5°
73.3°

Answer 1

For this case, we can use the following trigonometric relationship:

$tan(x) = \frac{C.O}{C.A}$

Where,

C.O: opposite leg

AC; adjacent leg

x: angle

Substituting values we have:

$tan(x) = \frac{3}{10}$

From here, we clear the value of x.

We have then:

$x = tan^{-1}(\frac{3}{10})\\x = 16.7$

Answer:

the angle at which the diagonal beam meets the 10-foot beam at the top of the frame is:

16.7°

Answer 2

The answer is 16.7 or answer a