Answer:
Embryological evidence
Explanation:
Deuterostomes is a group that includes echinoderms, hemichordates, and chordates. Although these animals exhibit a wide variety of body plans, they share a mouth secondarily formed during embryo development, which it is believed to be an evolutionarily derived character present between a common ancestor and all its descendants (i.e., a synapomorphy). This oral cavity is formed by the invagination of the ectoderm layer opposite to the blastopore of the gastrula.
Answer:
They concluded that these antibodies were a) Globular proteins
Explanation:
Globular proteins are known to be water-soluble, spherical in shape and to be polypeptides as well. Compared to the other options provided, the selected one is the most correct.
<span>You needed a quick boost of energy - MONOSACCHARIDE
You wanted to grow strong nails, you haven't eaten in days - PROTEIN
You wanted to grow healthy hair - PROTEIN
You had a race tomorrow afternoon - POLYSACCHARIDE
You were getting ready for hibernation - LIPIDS
You wanted to get bigger muscles - PROTEIN
Your meal will be in a week - LIPIDS
CARBOHYDRATES include monosaccharide and polysaccharides. They provide immediate energy boost or short term energy storage for animals as well as long term energy storage for plants.
PROTEIN s</span>peeds up chemical reactions by lowering activation energy. It is used to form bones and build muscles. It is m<span>ade up of an amino group, a carboxyl group, and an R group.
LIPIDS can be saturated or unsaturated fatty acids. They are not soluble in water however they provide long-term energy storage for animals. </span>
Answer:
p = 0.34
Explanation:
The green allele is recessive, meaning two copies of q (qq) are required to be green. Conversely, animals that are either pp or pq will be blue.
If 44 organisms are green, that means 44 are qq.
For genotype frequencies, the equation is:
homozygous dominant genotype + heterozygous + homozygous recessive = 100%
Which is denoted as
p² + 2pq + q² = 1
We know that q² = 44/100 = 0.44
To work out q, we can do 
= 0.66
For allele frequencies, the total must add up to 100%, so
p + q =1
We know that q= 0.66
So p = 0.34, because 0.66 + 0.34 = 1
