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2 years ago

Find the number of palindromes between 10,000 and 99,999 that are divisible by 25.

2 answers:

7 0

Numbers divisible with 25 are numerals ending with 00,25,50 or 75.
Between 10,000 and 99,999 divisible by 25 are the numbers: 10,000, 10,025, 10,050, ......, 99,975.
Palindrome is a number that reads the same forwards and backwards. Example is 11, 22, 121,...
In our number frame, palindrome numbers are : 10,0001 , 22,222, 33,333,
Divisible by 25 is the palindrome number 55,555.

Anna11 [10]2 years ago

3 0

Answer:

52025 palindromes between 10,000 and 99,999 that are divisible by 25.

Step-by-step explanation:

Given : Numbers between 10,000 and 99,999 .

To find : Find the number of palindromes between 10,000 and 99,999 that are divisible by 25.

Solution : We have given numbers between 10,000 and 99,999 .

Palindrome Numbers : that read the same backwards and forwards.

Example : 17371.

Numbers that divisible by 25 : numbers end with 0 , or 5

Example : 25 , 100 , 75 ......

We can see from given numbers palindromes between 10000 and 99999 are of the form abcba ,

Where, c can be 0 to 9

Like : 55555 , 52025, 52125 ,52225 , 52325 ......so on

Therefore, 52025 palindromes between 10,000 and 99,999 that are divisible by 25.

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2 years ago

Find the height of a clock tower if the angle of elevation from a horizontal point 430 m from its base is 40°.

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$\\ \sf\longmapsto tan40=\dfrac{P}{430}$

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2 years ago

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There are 9.5 ounces of juice in a container. An additional 1.75 ounces of juice are poured into the container each second. How

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2 years ago

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The exponential functions y=(1-25)^x-2/5. -10 is shown hraphed along woth the horizontal line y=115 their intersection is (a,115

evablogger [386]

Answer:26

Step-by-step explanation:

Y=1.25^x-2/5-10

Take log of both sides

So Y+10=1.25^x-2/5

So log to base 10 of the two sides of the equation is

Log(Y+10)=X-2/5log1.25.

To make X the subject, divide both sides by log1.25.

Log(Y+10)/log1.25=X-2/5.

Recall that Y was given to be 115

It becomes log(115 +10)/Log1.25=x-0.4

21.64=x-0.4

X=25.6

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2 years ago

A cell phone company charges a $10 flat fee plus $0.05 per minute for minutes up to 600. For minutes over 600, the company

mash [69]

Answer:

In both the cases, the given total amount is given as:

T = 10 + 0.05 m (when minutes talked m < 600)

T = 40 + 0.15 k (when minutes talked k > 600)

Step-by-step explanation:

Here, the flat fee by the phone company = $10

The charge for each minute for first 600 minutes = $0.05

The per minute cost after 600 minutes = $0.15

Let us assume the number of minutes talked = m

Case 1: when the minutes talked is less than 600 minutes.

Total Charges = Flat Fee + 0.05 x ( the minutes talked)

or, T = $10 + m ($0.05)

or T = 10 + 0.05 m (when m < 600)

Case 2: when the minutes talked is more than 600 minutes.

Let us assume the minutes talked over 600 = k minutes

Total Charges = Flat Fee + Charges for 600 minutes + 0.15 x ( the minutes talked over 600)

or, T = $10 + 600 ($0.05) + k($0.15)

or T = 10 + $30 + 0.15 k (when k > 600)

⇒ T = 40 + 0.15 k (when k > 600)

Hence, in both the cases, the given total amount is given as:

T = 10 + 0.05 m (when m < 600)

T = T = 40 + 0.15 k (when k > 600)

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2 years ago