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tensa zangetsu [6.8K]

2 years ago

9

Hannah and Leah are running around a circular track. Hannah takes 5 minutes to complete one lap, and Leah takes 6 minutes to com

plete one lap. If they both start at the same time and from the same point, they will be together at the starting point and then again after ______ minutes.

2 answers:

AlexFokin [52]2 years ago

6 0

Answer:

30 min

Step-by-step explanation:

Dima020 [189]2 years ago

4 0

The answer is 30 minutes. Because 6 x 5 = 30 while 5 6 = 30 as well. Hope this helped.

You might be interested in

How many times greater is the value of the 3 in 4,367 than the value of the 3 in 39?

Lesechka [4]

Answer: Roughly 111.97

Step-by-step explanation:

1. 39 divided by 3 is 13.

2. 4367 divided by 3 is not evenly distributed. Rounding, it would work out to be roughly 1455.66

3. 1455.66 divided by 13 is roughly 111.97 (Again, this does not distribute evenly)

4. To check your work, multiply 111.97 times 13 and you should get somewhere around 1455.66 which is (4367 divided by 3).

Hopefully this helps! Feel free to mark brainliest! :)

8 0

2 years ago

The hypotenuse of a 45°-45°-90° triangle measures 10 StartRoot 5 EndRoot in. A right triangle is shown. The hypotenuse has a len

suter [353]

Answer:

$5\sqrt{10}\ units$

5 StartRoot 10 EndRoot

Step-by-step explanation:

we know that

The legs of a 45°-45°-90° triangle are congruent

Let

x ----> the length of one leg of the triangle

Applying the Pythagorean Theorem

$c^2=a^2+b^2$

where

c is the hypotenuse

a and b are the legs

we have

$c=10\sqrt{5}\ units$

$a=b=x\ units$

substitute

$(10\sqrt{5})^2=x^2+x^2$

$500=2x^2\\x^2=250\\x=\sqrt{250}\ units$

Simplify

$x=5\sqrt{10}\ units$

5 StartRoot 10 EndRoot

4 0

2 years ago

Read 2 more answers

Define f(0,0) in a way that extends f to be continuous at the origin. f(x, y) = ln ( 19x^2 - x^2y^2 + 19 y^2/ x^2 + y^2) Let f (

kirill115 [55]

Answer:

f(0,0)=ln19

Step-by-step explanation:

$f(x,y)=ln(\frac{19x^2-x^2y^2+19y^2}{x^2+y^2})$ is given as continuous function, so there exist $lim_{(x,y)\rightarrow(0,0)}f(x,y)$ and it is equal to f(0,0).

Put x=rcosA annd y=rsinA

$f(r,A)=ln(\frac{19r^2cos^2A-r^2cos^2A*r^2sin^2A+19r^2sin^2A}{r^cos^2A+r^2sin^2A})=ln(\frac{19r^2(cos^2A+sin^2A)-r^4cos^2Asin^a}{r^2(cos^2A+sin^2A)})$

we know that $cos^2A+sin^2A=1$ , so we have that

$f(r,A))=ln(\frac{19r^2-r^4cos^2Asin^a}{r^2})=ln(19-r^2cos^2Asin^2A)$

$lim_{(x,y)\rightarrow(0,0)}f(x,y)=lim_{r\rightarrow0}f(r,A)=ln19$

So f(0,0)=ln19.

8 0

2 years ago

Problem number 26 of the Rhind Papyrus says: Find a quantity such that when it is added to of itself the result is a 15. The mod

Bess [88]

X+x=15 combine like terms on left side

2x=15 divide both sides by 2

x=7.5

4 0

2 years ago

Read 2 more answers

What is the numerator of the simplified sum? StartFraction x Over x squared + 3 x + 2 EndFraction + StartFraction 3 Over x + 1 E

ozzi

Answer:

4x + 6

Step-by-step explanation:

Given

$\frac{x}{x^2+3x+2}$ + $\frac{3}{x+1}$

Before we can add the fractions we require them to have a common denominator.

Factor the denominator of the first fraction

$\frac{x}{(x+1)(x+2)}$ + $\frac{3}{x+1}$

Multiply the numerator / denominator of the second fraction by (x + 2)

= $\frac{x}{(x+1)(x+2)}$ + $\frac{3(x+2)}{(x+1)(x+2)}$ ← fractions now have a common denominator

Add the numerators leaving the denominators

= $\frac{x+3(x+2)}{(x+1)(x+2)}$

= $\frac{x+3x+6}{(x+1)(x+2)}$

= $\frac{4x+6}{(x+1)(x+2)}$ ← simplified sum with numerator 4x + 6

7 0

2 years ago