Answer How many liters of a 20% acid solution should be mixed with 30 liters of 50% acid solution in order to obtain a 40% solution. ... x=15 liters 15*(.20 pure acid)=3 liters 30*(.50 pure acid)=15 liters That is 18 liters pure acid That is 45 liters solution *0.45 pure acid=18 liters.
As more pure acid is added, the concentration of acid approaches 0.
You can make about 11 burgers with that
Weight of an object=J
x=J/(379.2/150)
x=J/2.528
y=12.64/2.528
y=5
Hope this helps :)
The third table
Explanation:
6/4 = 1.5 , 9/6 = 1.5 , 12/8 = 1.5
