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strojnjashka [21]
2 years ago
3

Sally swam a total distance of 3 and 1 over 2 miles during the months of November and December. If Sally only swam 1 over 4 of a

mile every day, which expression shows the number of days she went swimming? ?
3 and 1 over 2 ⋅ 1 over 4
3 and 1 over 2 ÷ 1 over 4
3 and 1 over 2 + 1 over 4
3 and 1 over 2 – 1 over 4
Mathematics
2 answers:
Nezavi [6.7K]2 years ago
8 0

Answer:

The correct answer is 3 and 1 over . 1 over 4

Step-by-step explanation:

this is becuse when solvin this we use the "keep, change, flip." this means we keep the first fraction, change the sign and flip the last fraction. therefore meaning that optionn A is correct! GOODLUCK!

Anuta_ua [19.1K]2 years ago
4 0

Answer:

3 and 1 over 2 ÷ 1 over 4

Step-by-step explanation:

Given,

Total distance Sally swam = 3\frac{1}{2} miles,

Also, the distance she swims each day = \frac{1}{4} miles,

Hence, the number of days she went swimming = \frac{\text{Total distance}}{\text{One day distance}}

=\frac{3\frac{1}{2}}{\frac{1}{4}}

= 3 and 1 over 2 ÷ 1 over 4

Second option is correct.

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Question 14. A carousel makes one complete revolution every 75 seconds. Levi sits on the carousel 4 feet from its center. If the
garik1379 [7]

Answer:

The correct option is;

H. 32·π

Step-by-step explanation:

The given information are;

The time duration for one complete revolution = 75 seconds

The distance from the center of the carousel where Levi sits = 4 feet

The time length of a carousel ride = 5 minutes

Therefore, the number of complete revolutions, n, in a carousel ride of 5 minutes is given by n = (The time length of a carousel ride)/(The time duration for one complete revolution)

n = (5 minutes)/(75 seconds) = (5×60 seconds/minute)/(75 seconds)

n = (300 s)/(75 s) = 4  

The number of complete revolutions - 4

The distance of 4 complete turns from where Levi seats = 4 ×circumference of circle of Levi's motion

∴ The distance of 4 complete turns from where Levi seats = 4 × 2 × π × 4 = 32·π.

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2 years ago
Dale, Thomas, and Betty plan to split the cost of a round-trip car ride from
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2 years ago
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Un guardia forestal divisa, desde un punto de observación A, un incendio en la dirección N27° 10’ E. Otro guardia, que se encuen
Inga [223]

Answer:

la distancia del punto de observación A al incendio = 5.5 millas

la distancia del punto de observación B al incendio = 3.8 millas

Step-by-step explanation:

La expresión esquemática de la pregunta se puede ver en la imagen adjunta a continuación :

Del siguiente diagrama;

Usando la sine regla:

\dfrac{sin \  F}{f} = \dfrac{sin  \ A }{a}

\dfrac{sIn \  79}{6} = \dfrac{sin \   63}{a}

a sin 79 = 6 sin 63

a =\dfrac{6 \times sin \ 63}{sin \ 79}

a =\dfrac{6 \times 0.8910}{0.9816}

a = 5.446 millas

la distancia del punto de observación A al incendio = 5.5 millas (a la décima más cercana)

\dfrac{sin \  F}{f} = \dfrac{sin  \ B}{b}

\dfrac{sin \  79}{6} = \dfrac{sin  \ 38}{b}

b sin 79 = 6 sin 38

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b  = \dfrac{6 \times0.6157 }{0.9816}

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la distancia del punto de observación B al incendio = 3.8 millas (a la décima más cercana)

8 0
2 years ago
The yearly income for an individual with an associate’s degree in 2001 was $53,166 and in 2003 it was $56,970. What is the ratio
8090 [49]

Answer:

8861 : 9495

Step-by-step explanation:

Ratio of income in 2001 to 2003:

53,166 : 56,970

Then, you can simplify by dividing both sides by 6:

8,861 : 9,495

Can't simplify anymore, Therefore this is the answer!

8861 : 9495

Hope I helped! Have a good day :)

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I hope this helps you

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