Question

The yearly income for an individual with an associate’s degree in 2001 was $53,166 and in 2003 it was $56,970. What is the ratio of the income in 2001 to the income in 2003 in simplest form?

Answer 1

Answer:

$\frac{8861}{9495}$

Step-by-step explanation:

Income of an individual in 2001 = $\ 53,166$

Income of an individual in 2003 = $\ 56,970$

Here, we need to find ratio of income in 2001 to the income in 2003 in simplest form .

i.e we need to convert $\frac{\ 53,166}{\ 56,970}$ in simplest form .

A fraction $\frac{a}{b}$ is said to be in simplest form if $HCF(a,b)=1$

So, we will first find $HCF(53166,56970)$ then divide both numerator and denominator by the HCF .

Here,

$53166=2\times 3\times 8861$

$56970=2\times 3\times 3\times 3\times 5\times 211$

So, $HCF(53166,56970)=2\times 3=6$

On dividing both numerator and denominator by 6 , we get

$\frac{53166}{56970}=\frac{8861}{9495}$

Answer 2

Answer:

8861 : 9495

Step-by-step explanation:

Ratio of income in 2001 to 2003:

53,166 : 56,970

Then, you can simplify by dividing both sides by 6:

8,861 : 9,495

Can't simplify anymore, Therefore this is the answer!

8861 : 9495

Hope I helped! Have a good day :)