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2 years ago

Determine the factors of 15x2 + 3xy + 10x + 2y.

Mathematics

2 answers:

Phoenix [80]2 years ago

5 0

Letter A is the correct answer

Ganezh [65]2 years ago

4 0

Answer:

The correct option is a.

Step-by-step explanation:

The given expression is

$15x^2+3xy+10x+2y$

It can be written as

$(15x^2+10x)+(3xy+2y)$

Taking out the common factors from each parenthesis.

$5x(3x+2)+y(3x+2)$

Now, again taking out the common factors.

$(3x+2)(5x+y)$

Therefore the correct option is a.

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Answer:

A.Each side of the new triangle is 4 times shorter than the original.step explanation:

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2 years ago

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WHICH IS A TRUE STATEMENT BASED ON THE DOT PLOTS BELOW 10 POINTS

Nata [24]

Answer:

C. Set B has the greater range.

Step-by-step explanation:

We can start out with listing out each set of data in a way that makes it easier to work with.

Set A:

20,20,30,30,40,40,40,40,40,50,50,60,60,60

Set B:

10,10,20,20,20,30,30,30,30,40,50,50,60

We can start by trying to eliminate answer options; starting with D.

To get the mean of a set of data, we need to add all numbers in the data set and then divide by the number of dots on the plot.

For Set B: 10+10+20+20+20+20+30+30+30+30+40+50+50+60=420 then divide by number of dots (14) 420/14=30 The mean of Set B is equal to 30.

Solve the mean for Set A to compare. The mean is 41. D is not true so we can eliminate this answer choice.

We can look at the median of both sets so that we can eliminate answer choice B. The median is the middle most point in the set of data.

Set A median: 40

Set B median: 30

We can eliminate B because it does not have the greater median.

On to option C: range.

To find the range of each data set, we subtract the smallest number from the biggest number.

Set A: 60-20=40

Set B: 60-10= 50

Set B does in fact have a greater range than Set A. Answer choice C is the correct option.

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2 years ago

The formula for the area of a rhombus is A = a equals StartFraction one-half EndFraction d 1 d 2.d1d2, where d1 and d2 are the l

Strike441 [17]

Answer:

$\large\boxed{d_1=\dfrac{2A}{d_2};\ d_2=\dfrac{2A}{d_1}}$

Step-by-step explanation:

$A=\dfrac{1}{2}d_1d_2\qquad\text{multiply both sides by 2}\\\\2A=2\!\!\!\!\diagup\cdot\dfrac{1}{2\!\!\!\!\diagup}d_1d_2\\\\2A=d_1d_2\to d_1d_2=2A$

$\text{For}\ d_1:\\\\d_1d_2=2A\qquad\text{divide both sides by}\ d_2\neq0\\\\d_1=\dfrac{2A}{d_2}\\\\\text{For}\ d_2:\\\\d_1d_2=2A\qquad\text{divide both sides by}\ d_1\neq0\\\\d_2=\dfrac{2A}{d_1}$

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2 years ago

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Seams Personal advertises on its website that 95% of customer orders are received within four working days. They performed an au

Bezzdna [24]

Answer:

a. Yes(n=500>=5, n(1-p)=25>=5)

b. 0.15241

Step-by-step explanation:

a. A normal approximation to the binomial can be used $n\geq$ 5 and n(1-p)>=5:

#We calculate our p as follows:

$\hat p$ =x/n=470/500=0.94

n=500

n(1-p)=500(1-0.95)=25

Hence, we can use the normal approximation.

b. This is a normal approximation.

-Given that p=0.95(95%)

-We verify if our distribution can be approximated to a normal:

$np=0.95\times 500=475\\n(1-p)=500(1-0.95)=25\\\\np\geq 5,\ n(1-p)\geq 5$

Hence, we can use the normal approximation of the form:

$P_{bin}(k,n,p)->N(\mu,\sigma^2)\left \{ {{\mu=np=475} \atop {\sigma=\sqrt{np(1-p)}=4.8734}} \right. \\\\\\P_{bin}(k\leq 470)\approx P_{norm}(x\leq 470.5)=P_{norm}(z\leq \frac{470-475}{4.8734})\\\\P_{norm}(z\leq -1.0260)=0.15241$