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Ber [7]
2 years ago
11

What's the unit rate 975 revolutions in 3 mins​

Mathematics
1 answer:
cricket20 [7]2 years ago
3 0

Answer:

325 rpm's

Step-by-step explanation:

975 revolutions in 3 minutes

divide 975 by 3 to get the number of revolutions per minute (rpm)

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A marketing firm is considering making up to three new hires. Given its specific needs, the management feels that there is a 50%
IRISSAK [1]

Answer:

a) 0.9

b) Mean = 1.58

Standard Deviation = 0.89

Step-by-step explanation:

We are given the following in the question:

A marketing firm is considering making up to three new hires.

Let X be the variable describing the number of hiring in the company.

Thus, x can take values 0,1 ,2 and 3.

P(x\geq 2) = 50\%= 0.5\\P(x = 0) = 10\% = 0.1\\P(x = 3) = 18\% = 0.18

a) P(firm will make at least one hire)

P(x\geq 2) = P(x=2) + P(x=3)\\0.5 = P(x=2) + 0.18\\ P(x=2) = 0.32

Also,

P(x= 0) +P(x= 1) + P(x= 2) + P(x= 3) = 1\\ 0.1 + P(x= 1) + 0.32 + 0.18 = 1\\ P(x= 1) = 1- (0.1+0.32+0.18) = 0.4

\text{P(firm will make at least one hire)}\\= P(x\geq 1)\\=P(x=1) + P(x=2) + P(x=3)\\ = 0.4 + 0.32 + 0.18 = 0.9

b) expected value and the standard deviation of the number of hires.

E(X) = \displaystyle\sum x_iP(x_i)\\=0(0.1) + 1(0.4) + 2(0.32)+3(0.18) = 1.58

E(x^2) = \displaystyle\sum x_i^2P(x_i)\\=0(0.1) + 1(0.4) + 4(0.32) +9(0.18) = 3.3\\V(x) = E(x^2)-[E(x)]^2 = 3.3-(1.58)^2 = 0.80\\\text{Standard Deviation} = \sqrt{V(x)} = \sqrt{0.8036} = 0.89

7 0
2 years ago
At East Middle School, there are 58 left-handed students and 609 right-handed students. The numbers of left- and right-handed st
EastWind [94]

<u>Answer:</u>

C. Left-handed: 48, Right-handed: 504

D. Left-handed: 30, Right-handed: 315

<u>Step-by-step explanation:</u>

We are given that there are 58 left-handed students and 609 right-handed students at East Middle School and these numbers of students are proportional to the number of left and right handed students at East Middle School.

Given the above information, we are are to determine which two options could be the the numbers of left-handed and right-handed students at West Junior High.

Ratio of right handed to left handed students at East Middle School = \frac{609}{58} = 10.5

Checking for ratios of the given options:

A. \frac{483}{42} =11.5

B. \frac{378}{28} =13.5

C. \frac{504}{48} =10.5

D. \frac{560}{56} =10

E. \frac{315}{30} =10.5

Therefore, the possible numbers of left-handed and right-handed students at West Junior High could be C. Left-handed: 48, Right-handed: 504 and D. Left-handed: 30, Right-handed: 315.

7 0
2 years ago
Read 2 more answers
Find solution to the system of linear equations. 5x1 + x2 = 0 , 25x1 + 5x2 = 0
Zigmanuir [339]

Answer:

the system of equation has infinite solution

Step-by-step explanation:

5x_1 + x_2 = 0 , 25x_1 + 5x_2 = 0

Solve the first equation for x_2

Subtract 5x1 on both sides

5x_1 + x_2 = 0

x_2 =-5x_1

Now substitute -5x1 on second equation

25x_1 + 5x_2 = 0

25x_1 + 5(-5x_1)= 0

25x_1-25x_1= 0

0=0

So the system of equation has infinite solution

5 0
2 years ago
Read 2 more answers
IF AM = 10, then TC =?
iren [92.7K]
Hey there,

If AM= 10

We do 180 - 10.

And that would give us 170°

TC=170

Hope this helps.
~Jurgen
6 0
2 years ago
Read 2 more answers
A pond had 60 fish. 27 were carp and the rest were tench. 10 fish were added. The probability that a fish picked at random is a
ivanzaharov [21]

Answer: 2

<u>Explanation:</u>

A pond had 60 fish but 10 were added so now the pond has 70 fish.

The probability of choosing a carp is 1/2 so \frac{1}{2} (70) = 35 are now carp.  

There were 27 carp and now there are 35 carp so 8 carp were added.

10 fish were added and 8 of them were carp so 2 of them were tench.

6 0
2 years ago
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