Answer:
The first blank can be filled with tagging. One of the procedures for studying the movements, biology, and migration of animals is known as tagging of animals. Tagging is utilized to examine the long-range irregular and regular movements of animals and to identify their life-span. All kinds of mollusks, vertebrates, and insects can be tagged.
The second blank can be filled with designate their area as a national park. Designation of the areas as a national park is one of the methods of conserving animals, like a tiger.
Explanation:
C. is deactivated in a strongly acidic solution
When cells reach their size limitations one of two things will happen: they will either stop growing and split into two separate cells. Cell division can be both good and bad.
Answer:
Incomplete dominance
Co-dominance
Explanation:
Gregor Mendel discovered the principles that governs heredity, in which one of them is that an allele called DOMINANT allele, is capable of masking the expression of its variant allele called RECESSIVE allele in a heterozygous state. However, there has been genetic scenarios contrary to this his LAW OF DOMINANCE.
One of those Non-mendelian pattern of inheritance is a phenomenon called INCOMPLETE DOMINANCE, where an allele does not mask the expression of another completely, instead their combined state produces a third intermediate phenotype that is different from both parents. This is the case of the homozygous black bull mated with a homozygous white cow to produce a grey calf. The grey phenotype is an intermediate phenotype of both the black and white colours that forms due to incomplete dominance.
Another genetic scenario is called CO-DOMINANCE, where one allele is neither dominant nor recessive to the other allele, but instead both phenotypes becomes simultaneously expressed in the heterozygous offspring. In this case, the black bull and white cow were mated to form a heterozygous calf with both black and white spots.
This is the DNA. I'm going to only use the upper strand to demonstrate what this strand would code for before and after a single bp deletion (so write it as mRNA). I will also write it how it's easier to see this which is to split them up into the 3 base codon system. Note that you don't need to know the amino acid code - you use a table to find these.
ORIGINAL (mRNA on top, Amino Acid (AA) on bottom:
5'-AGC GGG AUG AGC GCA UGU GGC GCA UAA CUG-3'
SER GLY MET SER ALA CYS GLY ALA STOP LEU
Note that the protein would stop being made at the stop codon and the LEU wouldn't matter at the end...
Now, I will remove one bp...(I bolded it up top). Rewrite the mRNA and find the corresponding AA...
NEW
5'-AGC GGG AUG GCG CAU GTG GCG CAU AAC UG-3'
SER GLY MET ALA HIS VAL ALA HIS ASN .....
Completely different amino acid sequence after the methionine (MET). The stop codon is gone...the protein would continue being translated until it reaches another stop codon...so not what was supposed to be made!
