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2 years ago

Which situation could describe Yana’s activities in the computer lab?

2 answers:

8 0

First, when Yana opened her saved paper, she opened an existing Word file and edited its content. Then she edited her work and continued.

Second, when Yana began writing a new paper, she opened a blank Word file and began writing her paper and saved and edited her work.

She is practicing the skill of opening, creating, saving a Word file. <span />

spayn [35]2 years ago

8 0

Answer: it's A: took the test and its very simple if you stop to read it;

(Yana opened her saved paper, wrote, took a break, deleted some of the words, and then began writing again.)

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15. The price of a ticket for your office Christmas party is $17.75. So far you've sold 28 tickets. How much money should you ha

Marina CMI [18]

17.75 x 28 = 497
you answer is C

5 0

2 years ago

Here are Barry Bonds's home-run totals, mostly for the San Francisco Giants, during the years 1991 - 2005:25, 34, 46, 37, 33, 42

elixir [45]

Answer:

Refer the attached figure.

Step-by-step explanation:

Given : Here are Barry Bonds's home-run totals, mostly for the San Francisco Giants, during the years 1991 - 2005

The data A={25, 34, 46, 37, 33, 42, 40, 37, 34, 49, 73, 46, 45, 45}

To find : Modified box plot for this distribution?

Solution :

Arranging the data from lowest to highest,

{25,33,34,34,37,37,40,42,45,45,46,46,49,73}

Find the median of the data

As the data is even numbers so the median is

$M=\frac{40+42}{2}=\frac{82}{2}=41$

Median = 41

For Box plot Graph,

$q_1=Q(A,0)$

$q_1=25$

$q_2=Q(A,0.25)$

$q_2=34.75$

$q_3=Q(A,0.5)$

$q_3=41$

$q_4=Q(A,0.75)$

$q_4=45.75$

$q_5=Q(A,1)$

$q_5=73$

Plotting the Box plot of the data.

Refer the attached figure below.

8 0

2 years ago

Read 2 more answers

mr. rite wants his roof to be 90degrees at its peak and have a slope of -7/2 on the sunny side of the house. if the height of hi

ruslelena [56]

Answer:

60 feet

Step-by-step explanation:

The slope of the roof is the vertical distance over the horizontal distance. This means for very 7 feet vertical the roof spreads out 2 feet horizontal. So if the roof is 210 feet vertical, then the horizontal will be _____.

This is found by setting up a proportionand solving for the unknown distance.

$\frac{7}{2}=\frac{210}{y}$

7y = 2*210

7y = 420

y = 60

The horizontal distance will be 60 feet.

3 0

2 years ago

A cone is cut out of the center of a pyramid with a rectangular base. The rectangular base has side lengths of 15 and 10 units.

Mekhanik [1.2K]

Answer:

Volume of shaded portion = (600 - 36π) units³

Step-by-step explanation:

Volume of the shaded portion = Volume of pyramid - Volume of cone

Volume of pyramid = ⅓*l*w*h

Where,

l = length of base of pyramid = 15 units

w = width of base of pyramid = 10 units

h = height of pyramid = 12 units

Plug in the values to find the volume of the pyramid

Volume of pyramid = ⅓*15*10*12 = 5*10*12 = 600 units³

Volume of Cone = ⅓πr²h,

Where,

r = radius = ½ of diameter = ½ of 9 = 3 units

h = height = 12 units

Volume of Cone = ⅓*π*3²*12 = ⅓*π*9*12

= π*3*12 = 36π units³

Volume of shaded portion = (600 - 36π) units³

3 0

2 years ago

The function C(t) below relates outside temperature in degrees Fahrenheit to the number of cricket chirps per minute. It takes a

vekshin1

T is a linear function of C ==> T = mC + b Each additional chirp C corresponds to an increase in T of 0.25 ==> m = 0.25 T = 52 when C = 20 ==> 52 = 0.25(20) + b ==> b = 52 - 5 = 47 So T = 0.25C + 47 When C = 100 then T = 0.25(100) + 47 = 25 + 47 = 72 When C = 120 then T = 0.25(120) + 47 = 30 + 47 = 77 so the temperature range is between 72 and 77 when there are between 100 and 120 chirps per minute

3 0

2 years ago

Read 2 more answers