Cr{3+} + 3 NaF → CrF3 +
3 Na{+} <span>
First calculate the total mols of NaF.
(0.063 L) x (1.50 mol/L NaF) = 0.0945 mol NaF total </span>
Using stoichiometric
ratio:
<span>0.0945 mol NaF * (1 mol Cr3+ / 3 mol NaF) * (51.9961 g Cr3+/mol) =
1.6379 g Cr3+</span>
The first ionization energy of a known element is the energy
it needs to remove its highest energy or outermost electron. It is done to make
a neutral atom be a positively charged ion. The first ionization energy of neon
as a chemical equation is this:
Ne (g) -> Ne+ (g) + e-
