For the presence of ammonium ion, there is a need to add sodium hydroxide solution to the water and warm the mixture. Test any vapor that gets produced with damp red litmus paper. It should turn blue as ammonia gas is discharged, which is alkaline. The ionic equation for the reaction is:
NH₄⁺ + OH⁻ ⇒ NH₃ + H₂O
For the presence of phosphate ions, the addition of barium ions is done. The ionic equation is:
3Ba₂⁺ + 2PO4³⁻ ⇒ Ba₃ (PO₄)₂ (precipitate)
C. Sulfur and oxygen (non metals) forms a covalent bond while the magnesium (a metal) will react with both non metals to form an ionic bond
The number of moles of NaOh that are contained in 65ml of 2.20M solution NaOh in H2o is calculated using the below formula
moles = molarity x volume /1000
that is 65 x2.20 /1000= 0.143 moles
Answer:
EMF = -0.17 V
No
Explanation:
For the reaction :
Cd(s) + Fe2+(aq) → Cd2+(aq) + Fe(s)
we will be using the Nersnt equation to calculate Ecell:
Ecell = Eº -0.0592 V/2 ln Q
where Q = ( Fe⁺² )/ (Cd²⁺)
and (Fe²⁺) and (Cd²) are the molar concentration of Fe²⁺ and Cd²⁺
Reduction
Fe²⁺ + 2e⁻ ⇒ Fe(s) Eº red = -0.4400 V
Oxidation
Cd (s) ⇒ Cd²⁺ + 2e⁻ Eº ox = +0.4000 V
Eºcell = Eox + Ered = 0.4000 V + (-0.4400 V) = -0. 0400 V
Ecell = Eº -0.0692 V/2 ln Q = -0.0400 V - 0.0592/2 ln ( 0.80/0.010 ) = -0.17V
No because Eºcell is negative and ΔºG will be positive since
ΔºG = -nFEºcell
