Explanation:
Molarity is defined as number of moles divided by volume in liter.
Mathematically, Molarity =
Since, it is known that 1 L equals 1000 ml so 65.0 mL equals 0.065 L.
Therefore, it is given that volume is 0.065 L and molarity is 2.20 M. Hence, calculate number of moles as follows.
Molarity =
Number of moles =
=
= 0.143 mol
Thus, we can conclude that there are 0.143 moles NaOH are contained in 65.0 mL of a 2.20 M solution of NaOH in .
Answer : The new pressure acting on a 2.5 L balloon is, 8.6 atm.
Explanation :
Boyle's Law : It is defined as the pressure of the gas is inversely proportional to the volume of the gas at constant temperature and number of moles.
or,
where,
= initial pressure = 3.7 atm
= final pressure = ?
= initial volume = 5.8 L
= final volume = 2.5 L
Now put all the given values in the above equation, we get:
Thus, the new pressure acting on a 2.5 L balloon is, 8.6 atm.
Explanation:
A mixture is defined as the substance that contains two or more different number of substances that are physically mixed together.
For example, a mixture of air which contains oxygen, nitrogen and other gases.
A mixture in which solute particles are unevenly distributed into the solvent then it is known as a heterogeneous mixture.
For example, sand in water is a heterogeneous mixture.
A homogeneous mixture is defined as the mixture in which solute particles are evenly distributed in a solvent.
A homogeneous mixture is a clear solution.
For example, salt dissolved in water is a homogeneous mixture.
A solution is defined as the substance in which two or more substances are mixed together.
A compound is defined as the substance that contains two or more different elements that chemically combined together in a fixed ratio by mass.
A element is defined as the substance that contains only one type of atoms.
For example, a piece of sodium element will contain only atoms of sodium.
Whereas a pure substance is defined as the substance which contains only one type of molecule or one type of atom.
For example, ,
etc are pure substances.
Thus, we can conclude that the terms which could be used to describe the given sample of air is as follows.