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shusha [124]
1 year ago
10

The highest energy occupied molecular orbital in the f-f bond of the f2 molecule is _____

Chemistry
1 answer:
Morgarella [4.7K]1 year ago
3 0
The basis of finding the answer to this problem is to know the electronic configuration of Fluorine. That would be: <span>[He] 2s</span>²<span> 2p</span>⁵. The valence electrons, which are the outermost electrons of the atom, are the ones that participate in bonding. <em>Since the highest orbital for F is 2p, that means the highest energy occupied would be 2.</em>
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Which of the following actions cannot induce voltage in a wire?
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Your answer is D. Since there is little to no magnetic field to  wire, if it is copper which most wires are, there will be no voltage in a wire.
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Pesticides are best described as _______.
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Calculate ΔH∘ in kilojoules for the reaction of acetylene (C2H2) (ΔH∘f=227.4kJ/mol) with O2 to yield carbon dioxide (CO2) (ΔH∘f=
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Answer: The value of \Delta H^o for the reaction is, -2512.4 kJ

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The equation for the enthalpy change of the above reaction is:

\Delta H^o_{rxn}=[(3\times \Delta H^o_f_{(CO_2(g))})+(4\times \Delta H^o_f_{(H_2O(g))})]-[(1\times \Delta H^o_f_{(C_2H_2(g))})+(5\times \Delta H^o_f_{(O_2(g))})]

We are given:

\Delta H^o_f_{(H_2O(g))}=-241.8kJ/mol\\\Delta H^o_f_{(O_2(g))}=0kJ/mol\\\Delta H^o_f_{(CO_2(g))}=-393.5kJ/mol\\\Delta H^o_f_{(C_2H_2(g))}=227.4kJ

Putting values in above equation, we get:

\Delta H^o_{rxn}=[(4\times (-393.5))+(2\times (-241.8))]-[(2\times (227.4)+(5\times (0))]\\\\\Delta H^o_{rxn}=-2512.4kJ

Therefore, the value of \Delta H^o for the reaction is, -2512.4 kJ

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2 years ago
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The answer would be 0.25 g/mL. 
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<span>6 g / 24 mL = 0.25 g/mL </span>
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1 year ago
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