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2 years ago

Given a set of data, what steps would you take to identify whether the data showed linear or exponential growth?

2 answers:

5 0

The very first thing to do to identify whether the data showed linear or exponential growth is to plot the data. By plotting the data, you are able to visualize the form or trend of your data. You can also see if your data trend forms a line. If it forms a line, it is linear. If your data shows somehow a rapid increasing magnitude of slope then, it is exponential.

vovangra [49]2 years ago

3 0

Answer:

Make sure that the x-values are spaced apart in equal intervals.

Determine whether the y-values increase by the same amount or by the same ratio.

Decide that the data is linear because the y-values increase by a common difference.

Decide that the data is exponential because the y-values increase by a ratio or factor.

Step-by-step explanation:

You might be interested in

If a certain number of Grade IV students share 28 or 39 skill books in Mathematics,there are remainders of 4 and 3 books. What i

nadya68 [22]

Answer:

12 students

Step-by-step explanation:

<u>Below numbers are divisible by the number of students:</u>

28 - 4 = 24
39 - 3 = 36

24 = 2*2*2*3
36 = 2*2*3*3
GCF(24,36) = 2*2*3 = 12

The largest possible number of students is 12

7 0

1 year ago

Unless otherwise specified, the domain of a function f is assumed to be the set of all real numbers x for which f(x) is a real n

e-lub [12.9K]

Answer:

See Below

Step-by-step explanation:

The function is a piecewise function defined as:

$N(t)=\left \{ {{25t+150} \ 0 \leq t \leq 6 \atop {\frac{200+80t}{2+0.05t} \ t \geq 8}} \right.$

We need to find the limit of the function as t goes to infinity. This means what is the max value of fish in the pond given times goes to infinity (on an on).

We will take the 2nd part of the equation since t falls into that range, t is infinity, which is definitely greater than 8.

$\lim_{t \to \infty} \frac{200+80t}{2+0.05t} \\\lim_{n \to \infty} \frac{80t}{0.05t}\\ \lim_{n \to \infty} \frac{80}{0.05} =1600$

This means the maximum number of fish at this pond is 1600, no matter how long it goes on.

A function is continuous at a point if we have the limit and the functional value at that point same.

Functional value at t = 8 is (we use 2nd part of equation):

$\frac{200+80t}{2+0.05t}\\\frac{200+80(8)}{2+0.05(8)}\\=350$

We do have a value and limit also goes to this as t approaches 8.

So, function is continuous at t = 8

We want to find is there a "time" when the number of fishes in the pond is 250, during t from 0 to 6. We plug in 250 into N(t) and try to find t. Make sure to use the 1st part of the piece-wise function. Shown below:

$N(t)=25t+150\\250=25t+150\\25t=250-150\\25t=100\\t=4$

The time is 4 years when the number of fishes in the pond is 250

6 0

2 years ago

a used car dealer has a vehicle on the lot with a sticker price of $9999. if the dealer markup on used vehicles is 15%, how much

shepuryov [24]

$8694.78

Hope this helps!

5 0

2 years ago

Read 2 more answers

George still has 40 percent of his book to read. If George has read 180 pages, how many pages does he still have to read? How do

beks73 [17]

Answer: 72

Step-by-step explanation: so you do a line = line method the lines should look like they are fractions.

you do it for the both numbers the percent is always out of 100.

it should look like this

40% ?

--------- = -----------

100% 180

then you cross multiply 40 and 180 and than divide it by 100. your answer should be 72. you later replace the ? with 72

you know this because It is smaller than 180 and its bigger than the number 40.

5 0

2 years ago

Assume there are 365 days in a year.

MissTica

Answer:

1) The probability that ten students in a class have different birthdays is 0.883.

2) The probability that among ten students in a class, at least two of them share a birthday is 0.002.

Step-by-step explanation:

Given : Assume there are 365 days in a year.

To find : 1) What is the probability that ten students in a class have different birthdays?

2) What is the probability that among ten students in a class, at least two of them share a birthday?

Solution :

$\text{Probability}=\frac{\text{Favorable outcome}}{\text{Total number of outcome}}$

Total outcome = 365

1) Probability that ten students in a class have different birthdays is

The first student can have the birthday on any of the 365 days, the second one only 364/365 and so on...

$\frac{364}{365}\times \frac{363}{365} \times \frac{362}{365} \times \frac{361}{365}\times\frac{360}{365} \times \frac{359}{365} \times \frac{358}{365} \times \frac{357}{365} \times\frac{356}{365}=0.883$

The probability that ten students in a class have different birthdays is 0.883.

2) The probability that among ten students in a class, at least two of them share a birthday

P(2 born on same day) = 1- P( 2 not born on same day)

$\text{P(2 born on same day) }=1-[\frac{365}{365}\times \frac{364}{365}]$

$\text{P(2 born on same day) }=1-[\frac{364}{365}]$

$\text{P(2 born on same day) }=0.002$

The probability that among ten students in a class, at least two of them share a birthday is 0.002.

6 0

2 years ago